area =75 y'bs ft. Area =. %3D Width =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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length U
sth x length
width (W)
de of a rectangle.
de of a rectangle.
sq.ft.
_ft.
Area =
80
Width =
Area = width x length
80 =8 x length
80
Therefore, length
10
ft.
area = 75
5
Area =
sq.ft.
_ft.
Width
%3|
Area = width x length
%3D
%3D
Therefore, length =
ft.
4
area = 98
Area =
sq.ft.
_ft.
Width =
Transcribed Image Text:length U sth x length width (W) de of a rectangle. de of a rectangle. sq.ft. _ft. Area = 80 Width = Area = width x length 80 =8 x length 80 Therefore, length 10 ft. area = 75 5 Area = sq.ft. _ft. Width %3| Area = width x length %3D %3D Therefore, length = ft. 4 area = 98 Area = sq.ft. _ft. Width =
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