3.12 The following data are obtained when open-circuit and short-circuit testsare performed on a single-phase, 50-kVA, 2400/240-volt, 60-Hz distribu-tion transformer.VOLTAGECURRENTPOWER(volts)(amperes)(watts)Measurements on low-voltage sidewith high-voltage winding openMeasurements on high-voltage sidewith low-voltage winding shorted2404.8517352.020.8650 (a) Neglecting the series impedance, determine the exciting admittancereferred to the high-voltage side. (b) Neglecting the exciting admittance,determine the equivalent series impedance referred to the high-voltageside. (c) Assuming equal series impedances for the primary and referredsecondary, obtain an equivalent T-circuit referred to the high-voltage side.

O.C Test: 240V, 4.85A, 173W S.C Test: 52V, 20.8A, 650W P∘=173W, V∘=240V,…

Answered: are performed on a single-phase,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

The losses found in a transformer
It belongs to the no-load (no-load) operation of the 36/240 V phase transformer and a phase measured from the short-circuit test. values are given in the table below. High voltage by applying rated voltage to the low voltage winding (The winding ends were left em pty and the unloaded test results were obtained. Rated currents to high voltage gates The decreasing energies were obtained in a short time from a short circuit by applying tests In direct current test The transformer with 1 V direct voltage applied to the low voltage winding draws 500 A direct current. All equivalent Calculate the circuit elements moved to the low voltage side. Boşta çalışma testi Güç Gerilim Akım 36 V 68 W 2,8 A Kısa devre testi Gerilim Güç Akım 15 V 325 W 42,2 A |
TRUE or FALSE: If a transformer is loaded from full-load value to half-load value, then the amount of core loss is also halved.
Q10) For the transformer shown in Figure below, determine (i) The turns ratio of the transformer (ii) The secondary current (iii) The voltage across the load R = 10k2 (iv) The voltage across the primary winding Ip = 3A Is = ? Ns = 20 turns RL Np = 60 turns 10k2 ellle lelll
C2 (i). Draw the Schematic diagram and explain the working of LVDT and write any two applications of it. (ii) A 12 kVA, 56HZ, single-phase transformer has a turns ratio of 18 : 2 and is supplied from a 2.5 kV supply. Neglecting losses, determine (a) the secondary voltage, (b) the full load primary current, (c) the maximum flux and (d) the minimum value of load resistance which can be connected across the secondary winding without the kVA rating being exceeded secondary voltage primary current maximum flux secondary resistance
The number of turns on the primary and secondary windings of a 1- transformer are 380 and 40 respectively. If the primary is connected to a 2.2 kV, 50-Hz supply, then the secondary voltage on no-load is
A 1100/170V, 50 HZ, 1-phase transformer with cross sectional area of the core is 30 cm? and maximum flux density is 1.5 wb/m2. The number of turns required on the LT side will be
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2. What is tap changing of transformer? Why it is needed?
Find the elements of the equivalent circuit attributed to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuit are 200 volts and 400 volts, respectively, with a frequency of 50 Hz. The primary no-load current at the voltage of 200 volts is 0.7 amperes and the loss of the core is equal to 70 watts. The resistance and reactance of the primary are 3.2 ohms and 1.25 ohms, respectively. The resistance and reactance of the secondary are 0.6 ohm and 0.07 ohm, respectively. Draw the equivalent circle, showing the values of its elements.
4. 100 kVA, 6800-240 V, 50 Hz single phase step down transformer has the following parameters: RLs-0.008Ω RHs-2.6Ω Ri-HS-500 0Ω XLS-0.015Ω XHs=5.22 Xm,HS=88002 Transformer is delivering 80% of rated load at rated voltage and 0.95 lagging power factor. Determine the following: a) The equivalent impedance of the transformer referred to primary. b) Input impedance of the combined transformer and load. c) Actual input voltage at HV side. d) Input impedance if load is disconnected. e) Exciting current at no load.
4. Why the efficiency of the transformer is high at half load compared to full load?

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are performed on a single-phase, 50-kVA, 2400/240-volt, 60-Hz distribu- tion transformer. VOLTAGE (volts) CURRENT (amperes) POWER (watts) leasurements on low-voltage side with high-voltage winding open leasurements on high-voltage side with low-voltage winding shorted 240 4.85 173 52.0 20.8 650