are normally distributed with a mean of 64 ounces and a standard deviation of 0.42 ounce. He has an engineering recalibration machine in attempt to lower the standard deviation. After recalibration, the quality-control manager randomly selects 19 bottles from the line and determines that the standard deviation is 0.38 ounce. Is there less variability in the filling machine? Use a 0.1. The null and alternative hypothesis would be: Ho: o 0.38 Hoo 0.42 Ho = 64 Ho: = 0.38 Ho: o |Ηι:σ <0.38 Ηι:σ <0.42 H :μ >64_H:μ <0.38 H:σ < 64 64 O O O O O The test is: ✓ right-tailed left-tailed two-tailed o O O O Based on a sample of 19 bottles, The test statistic is: The p-value is: Based on both the p-value method, we: Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals) (to 2 decimals)

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A machine fills bottles with 64 ounces of liquid. The quality-control manager determines that the fill levels
are normally distributed with a mean of 64 ounces and a standard deviation of 0.42 ounce. He has an
engineering recalibration machine in attempt to lower the standard deviation. After recalibration, the
quality-control manager randomly selects 19 bottles from the line and determines that the standard
deviation is 0.38 ounce. Is there less variability in the filling machine? Use a 0.1.
The null and alternative hypothesis would be:
Hoo 0.38 Ho: o
0.42 Ho = 64 Ho: p=0.38 Ho: o 64 0
H₁:0 <0.38 H₁:o<0.42 H₁:μ> 64 H₁ μ<0.38 H₁ : 0 < 64
O
O
O
O
The test is:
right-tailed left-tailed two-tailed o
O
O
O
Based on a sample of 19 bottles,
The test statistic is:
The p-value is:
Based on both the p-value method, we:
● Fail to reject the null hypothesis
O Reject the null hypothesis
(to 2 decimals)
(to 2 decimals)
Transcribed Image Text:A machine fills bottles with 64 ounces of liquid. The quality-control manager determines that the fill levels are normally distributed with a mean of 64 ounces and a standard deviation of 0.42 ounce. He has an engineering recalibration machine in attempt to lower the standard deviation. After recalibration, the quality-control manager randomly selects 19 bottles from the line and determines that the standard deviation is 0.38 ounce. Is there less variability in the filling machine? Use a 0.1. The null and alternative hypothesis would be: Hoo 0.38 Ho: o 0.42 Ho = 64 Ho: p=0.38 Ho: o 64 0 H₁:0 <0.38 H₁:o<0.42 H₁:μ> 64 H₁ μ<0.38 H₁ : 0 < 64 O O O O The test is: right-tailed left-tailed two-tailed o O O O Based on a sample of 19 bottles, The test statistic is: The p-value is: Based on both the p-value method, we: ● Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals) (to 2 decimals)
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