Are families with kids (population 1) less likely than families without kids (population 2) to display holidaydecorations? To answer the question, we would like to construct a 95% confidence interval using thefollowing statistics.37 of the 71 families with kids surveyed display holiday decorations and 25 of the 73 families without kidssurveyed display holiday decorations.a. The 95% confidence interval is (please show your answers to 3 decimal places)« Pi - P2b. We observe thatO all values in the confidence interval are above zerothe confidence interval contains zeroO all values in the confidence interval are below zeroc. From the confidence interval above, we can conclude that, in general, families with kids areSelect an answer V likely than families without kids to display holiday decorations with 95%confidence.

We want to calculate the 95% confidence interval

Answered: Are families with kids (population 1)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If n=15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
If n=29, x¯(x-bar)=31, and s=8, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 378 randomly selected caterpillars observed, 45 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 378 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 29 20 34 83 Female 43 26 25 94 Total 72 46 59 177 Use the table above to get a 90% confidence interval for the percentage of all female students who would receive a grade of A on this test.Enter your answers below using decimals. < P <
Are families with kids (population 1) just as likely than families without kids (population 2) to display holiday decorations? To answer the question, we would like to construct a 80% confidence interval using the following statistics. 21 of the 75 families with kids surveyed display holiday decorations and 26 of the 93 families without kids surveyed display holiday decorations. a. The 80% confidence interval is (please show your answers to 3 decimal places) -0.099 X P1 P2 <0.101 X
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
If n=20, ¯xx¯(x-bar)=43, and s=10, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
If n=16, x¯(x-bar)=48, and s=7, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
you conducted additional studies with these men and found the following: a. The RR for those who drank one drink per day was 1.50 (95% CI:1.32-1.67) in comparison to the abstainers. b. For those men who drank three or more drinks per day the RR compared to the abstainers was 4.20 (95% CI 2.68-5.85). Question: We can tell from the Confidence Intervals provided in #7 whether there are likely more people in the “one drink a day” group or the “3+ drinks per day” group. Which one likely has more people and how can we tell?
If n-10, 2(xbar)-40, and s-4, construct a confidence interval at a 98% confidence level. Assume the data. came from a iormally distributed population. Give your answers to one decimal place.
What if we're able to use a normal model. To construct a 95% Confidence Interval, we use the following formula: p hat ± ME for 95% CI If p hat = 0.38 and ME for 95% CI = 0.096, what is CI? Keep the numbers in 3 decimal places. Put the two numbers in ( ) and use a comma, then a space between the two numbers.

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