Archimedes® Principle A spherical buoy has a radius of I m and a density one-fourth that of seawater. By Archimedes Principle, the weight of the displaced water will equal the weight of the buoy. • Let x = the depth to which the buoy sinks. • Let d = the density of seawater. • Let r= the radius of the circle formed where buoy, air, and water meet. See the figure below. Notice in the figure that r² = 1 – (1 – x)² = 2x – x², and recall from geometry that the volume of submerged spherical TX cap is V = 6. * (3r² + x²). (d)Approximate the depth to which the buoy will sink.
Archimedes® Principle A spherical buoy has a radius of I m and a density one-fourth that of seawater. By Archimedes Principle, the weight of the displaced water will equal the weight of the buoy. • Let x = the depth to which the buoy sinks. • Let d = the density of seawater. • Let r= the radius of the circle formed where buoy, air, and water meet. See the figure below. Notice in the figure that r² = 1 – (1 – x)² = 2x – x², and recall from geometry that the volume of submerged spherical TX cap is V = 6. * (3r² + x²). (d)Approximate the depth to which the buoy will sink.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Archimedes® Principle A spherical buoy has a radius
of I m and a density one-fourth that of seawater. By Archimedes
Principle, the weight of the displaced water will equal the
weight of the buoy.
• Let x = the depth to which the buoy sinks.
• Let d = the density of seawater.
• Let r= the radius of the circle formed where buoy, air, and
water meet. See the figure below.
Notice in the figure that r² = 1 – (1 – x)² = 2x – x², and
recall from geometry that the volume of submerged spherical
TX
cap is V =
6.
* (3r² + x²).
(d)Approximate the depth to which the buoy will sink.
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