AR Example 1: Design a rigid-boundary earth channel (a=0.03) to carry a discharge of 250 A½. Assumptions: 1. Based on the topography and channel alignment. S = 0.1% 2. For a clean carth channel, n=0.03. 3. Designing a trapezoidal channel with a side slope of 1:3 (V:H), and bottom width of 5 ft. (a) 10- 3³ {15+34/4] [ \$+1y/y771/3 159.175=f14) Y= 4.75 ft 195 1 Rectangular Ynxb 0.01+ 0.001 0.01 0.1 1 10 100 (Q) xax. tike = 2.2 223. 4
AR Example 1: Design a rigid-boundary earth channel (a=0.03) to carry a discharge of 250 A½. Assumptions: 1. Based on the topography and channel alignment. S = 0.1% 2. For a clean carth channel, n=0.03. 3. Designing a trapezoidal channel with a side slope of 1:3 (V:H), and bottom width of 5 ft. (a) 10- 3³ {15+34/4] [ \$+1y/y771/3 159.175=f14) Y= 4.75 ft 195 1 Rectangular Ynxb 0.01+ 0.001 0.01 0.1 1 10 100 (Q) xax. tike = 2.2 223. 4
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter16: Highway Drainage
Section: Chapter Questions
Problem 16P
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Question
please help break down hydrology problem quickly. I have some notes on there. WHAT does Km stand for?
![AR
Example 1:
Design a rigid-boundary earth channel (a=0.03) to carry a discharge of 250 A½.
Assumptions:
1. Based on the topography and channel alignment. S = 0.1%
2. For a clean carth channel, n=0.03.
3. Designing a trapezoidal channel with a side slope of 1:3 (V:H), and bottom width of 5 ft.
(a) 10-
3³ {15+34/4] [ \$+1y/y771/3
159.175=f14)
Y= 4.75 ft
195
1
Rectangular
Ynxb
0.01+
0.001
0.01
0.1
1
10
100
(Q)
xax. tike = 2.2
223. 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc02cea10-2b20-4726-bfe2-8f9101f448fb%2F39fee119-c46f-4faf-ab13-236b8fbaa2f3%2F0shdqbb_processed.png&w=3840&q=75)
Transcribed Image Text:AR
Example 1:
Design a rigid-boundary earth channel (a=0.03) to carry a discharge of 250 A½.
Assumptions:
1. Based on the topography and channel alignment. S = 0.1%
2. For a clean carth channel, n=0.03.
3. Designing a trapezoidal channel with a side slope of 1:3 (V:H), and bottom width of 5 ft.
(a) 10-
3³ {15+34/4] [ \$+1y/y771/3
159.175=f14)
Y= 4.75 ft
195
1
Rectangular
Ynxb
0.01+
0.001
0.01
0.1
1
10
100
(Q)
xax. tike = 2.2
223. 4
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