Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). If 2.51 g of water is produced from the reaction of 9.8 g of hydrochloric acid and 6.4 g of sodium hydroxide, calculate the percent yield of water. Round your answer to 2 significant figures. X do ba
Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). If 2.51 g of water is produced from the reaction of 9.8 g of hydrochloric acid and 6.4 g of sodium hydroxide, calculate the percent yield of water. Round your answer to 2 significant figures. X do ba
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![Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). If 2.51 g
of water is produced from the reaction of 9.8 g of hydrochloric acid and 6.4 g of sodium hydroxide, calculate the percent yield of water.
Round your answer to 2 significant figures.
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Explanation
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Transcribed Image Text:Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O). If 2.51 g
of water is produced from the reaction of 9.8 g of hydrochloric acid and 6.4 g of sodium hydroxide, calculate the percent yield of water.
Round your answer to 2 significant figures.
esc
option
1
1
Explanation
!
A
Z
e
2
W
S
Check
X
command
X
#
3
E
D
C
Ś
$
4
R
F
5
V
T
G
A
6
B
MacBook Pro
Y
H
&
7
N
U
J
Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility
*
8
M
I
<
(
9
K
O
V -
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)
O
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Expert Solution
Step 1
The reaction between HCl and NaOH is
HCl + NaOH -------------> NaCl + H2O
Given ,
Mass of HCl = 9.8 g
Mass of NaOH = 6.4 g
Mass of water formed = 2.51 g
We have to calculate the percentage yield of water
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