approximately 60% of his or her maximum heart rate. For 20-year-olds, this rate is approximately 120 bpm. A simple random sample of thirty 20-year-olds was taken, and the sample mean was found to be 107 bpm, with a standard deviation of 45 bpm. Researchers wonder if this is evidence to conclude that the expected level is actually lower than 120 bpm. Choose the test statistic: MSG O F = MSE -Ho O = (0-E) O x? = E() p-Po O z= Po(1-Po
approximately 60% of his or her maximum heart rate. For 20-year-olds, this rate is approximately 120 bpm. A simple random sample of thirty 20-year-olds was taken, and the sample mean was found to be 107 bpm, with a standard deviation of 45 bpm. Researchers wonder if this is evidence to conclude that the expected level is actually lower than 120 bpm. Choose the test statistic: MSG O F = MSE -Ho O = (0-E) O x? = E() p-Po O z= Po(1-Po
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:When engaging in weight-control (fitness/fat burning) types of exercise, a person is expected to attain
approximately 60% of his or her maximum heart rate. For 20-year-olds, this rate is approximately 120
bpm. A simple random sample of thirty 20-year-olds was taken, and the sample mean was found to be
107 bpm, with a standard deviation of 45 bpm. Researchers wonder if this is evidence to conclude
that the expected level is actually lower than 120 bpm.
Choose the test statistic:
MSG
O F =
MSE
-Ho
O t=
s/Vn
O x² =
(0-E)?.
z =
Po(1-Po
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