Approximate the normal probability with an error of less than 0.0001, where the probability is given by (Round your answer to four decimal places.) 1 b VZπ e-x²/12 dx 2п P(a < x < b) = 1 1 = √ Le 2πT P(0 < x < 1) = e-x²/2 dx x 1 4 a b 7 2πT (x) = -√2/2² -32²12² n = 0 (-1)" 2n! (2n+1) = 0.3413 X

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