Applying the continuity correction to use the normal approximation to the binomial distribution, it was determined that the requested probability is P(34.5 ≤ x ≤ 40.5). Recall the formula to convert a random variable x to the standard normal random variable, z, given the mean , and standard deviation a. 2 = Recall that the mean was found to be μ = 30, and the standard deviation was found to be a = √24. Calculate the standard normal random variable z for the lower bound x = 34.5, rounding the result to two decimal places. = 28.37 z = = x-μ G x-μ √24 34.5-30 = z = Calculate the standard normal random variable z for the upper bound x = 40.5, rounding the result to two decimal places. x-μ х-и G x-μ √24 40.5 30 34.38 √24 x √24 x

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Applying the continuity correction to use the normal approximation to the binomial distribution, it was determined that the requested probability is P(34.5 ≤ x ≤ 40.5). Recall the formula to convert a random
variable x to the standard normal random variable, z, given the mean u, and standard deviation o.
Z =
Recall that the mean was found to be μ = 30, and the standard deviation was found to be o = √24. Calculate the standard normal random variable z for the lower bound x = 34.5, rounding the result to two
decimal places.
=
= 28.37
Z =
Z=
x-μ
σ
x-μ
√24
34.5 30
=
-
Calculate the standard normal random variable z for the upper bound x = 40.5, rounding the result to two decimal places.
= 34.38
x-μ
σ
x-μ
σ
x-μ
√24
40.5 - 30
√ 24
X
√24
X
Transcribed Image Text:Applying the continuity correction to use the normal approximation to the binomial distribution, it was determined that the requested probability is P(34.5 ≤ x ≤ 40.5). Recall the formula to convert a random variable x to the standard normal random variable, z, given the mean u, and standard deviation o. Z = Recall that the mean was found to be μ = 30, and the standard deviation was found to be o = √24. Calculate the standard normal random variable z for the lower bound x = 34.5, rounding the result to two decimal places. = = 28.37 Z = Z= x-μ σ x-μ √24 34.5 30 = - Calculate the standard normal random variable z for the upper bound x = 40.5, rounding the result to two decimal places. = 34.38 x-μ σ x-μ σ x-μ √24 40.5 - 30 √ 24 X √24 X
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