Apply the translation theorem to find the inverse Laplace transform of the following function. 6s+9 F(s) = S²-8s +41 L-' {F(s)} = t Table of Laplace transforms f(t)=¹(F(s)} L{f(t)} = F(s) f(t)=¹(F(s)) L{f(t)} = F(s) (s> 0) cos kt (s>0) sin kt 2 TETE n! (s> 0) cosh kt (s> |k|) s²-4² г(а+1) (s> 0) sinh kt (s>a) tª 1 S 1 n+1 1 s-a s²+k² k S k s²-K² (please enter an expression + as the variable) using n! (s-a)+1 (s>0) (s > 0) (s> |kl) (s>a)
Apply the translation theorem to find the inverse Laplace transform of the following function. 6s+9 F(s) = S²-8s +41 L-' {F(s)} = t Table of Laplace transforms f(t)=¹(F(s)} L{f(t)} = F(s) f(t)=¹(F(s)) L{f(t)} = F(s) (s> 0) cos kt (s>0) sin kt 2 TETE n! (s> 0) cosh kt (s> |k|) s²-4² г(а+1) (s> 0) sinh kt (s>a) tª 1 S 1 n+1 1 s-a s²+k² k S k s²-K² (please enter an expression + as the variable) using n! (s-a)+1 (s>0) (s > 0) (s> |kl) (s>a)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Apply the translation theorem to find the
inverse Laplace transform of the following function.
F(s)=-
6s+9
S²-8s +41
L₁' {F(s)} =
t
Table of Laplace transforms
f(t)=¹(F(s)} L{f(t)} = F(s) f(t)=1¹(F(s)} L{f(t)}=F(s)
(s> 0)
cos kt
(s> 0)
sin kt
²
s²+k²
TETE
n!
(s> 0)
cosh kt
s²-k²
г(а+1)
(s> 0)
sinh kt
(s>a)
1
S
1
n+1
1
s-a
s²+k²
k
S
k
s²-k²
(please enter an expression
+ as the variable)
using
n!
(s-a)n+1
(s>0)
(s > 0)
(s> |k|)
(s> |k|)
(s>a)
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