Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Apply the significant figure rules to the final answer. The rules are attached. The final answer will not be 5.73.
![Significant Figure Rules
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that lacks
a decimal point are not significant.
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or after the decimal point.
1
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ca43eaf-b19e-4dd7-8adb-ced009424530%2Fc7bdf3c6-6a1b-470a-95c1-8900176130fd%2F97dff8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Significant Figure Rules
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that lacks
a decimal point are not significant.
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or after the decimal point.
1
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.
![个
Giveni-
Balanced reaction
2KOH (9) +H₂g)
20.0g
Calculate liters of H₂ created from the above
2K(s) + 2H₂O(1)
mass of K = 20.0₁
reaction
Moler masses
K = 39·10 g/mol
4₂0= 18.02 g/mol
KOH = 56.11 g/mol
H₂ = 2.02 g/mol
Step 2
2Kcs) + 2H₂O(l)
moles
mars 20.0g
liters
{ K moler mass
K X Imol k
20.0g)
39.10g k
= 5.73 H₁₂
2KOH (9) + H₂(g)
= 39·10g/mol }
X
5.73 L
Imol H₂
2
2 mol K
2.
X 22.4L4₂
Imol H₂
3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ca43eaf-b19e-4dd7-8adb-ced009424530%2Fc7bdf3c6-6a1b-470a-95c1-8900176130fd%2Fk6bmsn5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:个
Giveni-
Balanced reaction
2KOH (9) +H₂g)
20.0g
Calculate liters of H₂ created from the above
2K(s) + 2H₂O(1)
mass of K = 20.0₁
reaction
Moler masses
K = 39·10 g/mol
4₂0= 18.02 g/mol
KOH = 56.11 g/mol
H₂ = 2.02 g/mol
Step 2
2Kcs) + 2H₂O(l)
moles
mars 20.0g
liters
{ K moler mass
K X Imol k
20.0g)
39.10g k
= 5.73 H₁₂
2KOH (9) + H₂(g)
= 39·10g/mol }
X
5.73 L
Imol H₂
2
2 mol K
2.
X 22.4L4₂
Imol H₂
3.
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