Apply the loop rule to loop aedcba in the figure below. E, = 18 V b I2 12 0.5 2 R2 2.5 Q 12 R, a e 13 6.0 2 R3 1.52 f 0.5 Q E2 = 45 V O (1,R,) + (I,r,) - E, + (1,R2) = 0 O (1,R2) + (I2";) - Ez + (I,R3) = 0 O (1,R3) – (12r2) + E, + (I,R3) = 0 O (1,R2) + (I2r2) – E, + (I,R,) = 0

Apply the loop rule to loop aedcba in the figure below. E, = 18 V b I2 12 0.5 2 R2 2.5 Q 12 R, a e 13 6.0 2 R3 1.52 f 0.5 Q E2 = 45 V O (1,R,) + (I,r,) - E, + (1,R2) = 0 O (1,R2) + (I2";) - Ez + (I,R3) = 0 O (1,R3) – (12r2) + E, + (I,R3) = 0 O (1,R2) + (I2r2) – E, + (I,R,) = 0

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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