Apply the Central Limit Theorem for Sample MeansA company produces steel rods. The lengths of the steelrods are normally distributed with a mean of 199 cm and astandard deviation of 2.3 cm. For shipment, a randomsample of 18 steel rods are bundled together.Find the probability that the mean length of a randomsample of 18 steel rods is less than 199.3 cm. Round youranswer to 3 decimal places.P(M < 199.3) =

From the provided information, Mean (µ) = 199 cm Standard deviation (σ) = 2.3 cm X~N (199, 2.3) Here…

Answered: Apply the Central Limit Theorem for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 151 cm and a standard deviation of 1.5 cm. For shipment, a random sample of 30 steel rods are bundled together.Find the probability that the mean length of a random sample of 30 steel rods is greater than 151.1 cm. Round your answer to 3 decimal places.P(M > 151.1) =
Ana is a dedicated Skee Ball player who always rolls for the 50-point slot. The probability distribution of Ana's score X on a randomly selected roll of the ball is shown here. The mean of this probability distribution is 23.8. Score Probability 10 0.32 20 30 40 0.27 0.19 0.15 50 0.07 What is the standard deviation of X? Interpret this value. σχ 12.632. The score of a randomly selected Skee Ball roll will typically vary from the mean (23.8) by about 12.632. = ox= 159.56. The score of a randomly selected Skee Ball roll will typically vary from the mean (23.8) by about 159.56. Oox = 159.56. The score of a randomly selected Skee Ball roll will vary from the mean (23.8) by 159.56. The standard deviation cannot be calculated in this situation because we do not have a list of randomly selected Skee ball point values. x = 12.632. The score of a randomly selected Skee Ball roll will vary from the mean (23.8) by 12.632.
The daily electric consumption of two houses were recorded. House A has consumes 375W (mean) the standard deviation is 15W. While House B uses 250W (mean), the standard deviation is 22W. 1. Find the probability for each house that the electric usage will not exceed 400W.2. Find the probability that both houses will exceed 400W in usage.3.Given the probability of 0.02, how much electricity must House B consume to avoid exceeding?
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 175.2-cm and a standard deviation of 1.8-cm. For shipment, 20 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is greater than 176.2-cm.P(M > 176.2-cm) = ________Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
The mean weight of all Goliath grouper caught on the Treasure coast is 377 pounds, with a standard deviation of 72 pounds. Suppose a random sample of 37 Goliath Grouper from the Treasure Coast are caught and weighed. Determine the probability that the average weight of the sample of 37 Goliath Grouper is within 31 pounds of the average weight of all Goliath Grouper caught on the Treasure Coast. Round the solution four decimal places, if necessary.
The average grade for an exam is 74, the standard deviation is 7 and the grades are curved to follow a normal distribution. Find the probability that a student will get a grade from 81 to 88 Select one: O a. 0.451 b. 0.612 O c. 0.1359 O d. 0.561
Apply the Central Limit Theorem for Sample Means A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 230 cm and a standard deviation of 1.6 cm. For shipment, a random sample of 35 steel rods are bundled together.Find the probability that the mean length of a random sample of 35 steel rods is greater than 230.2 cm. Round your answer to 3 decimal places.P(M > 230.2) =
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1522 and the standard deviation was 311. The test scores of four students selected at random are 1950, 1260, 2190, and 1410. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1950 is. (Round to two decimal places as needed.)
average number of pounds of meat that a person consumes per year is 218pounds. Assume that the standard deviation is 26 pounds and the distribution is approximately normal. 1- Find the probability that a person selected at random consumes less than 224 pounds per year 2-1f a sample of 50 individuals is selected find the probability that the mean of the sample will be less than 224 pounds per year
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1458 and the standard deviation was 312. The test scores of four students selected at random are 1860, 1220, 2150, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1860 is (Round to two decimal plaes as needed.)

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