Apply Newton's method twice to approximate 3. Use the initial approximation xo = 3. (You need to find out x1 and x2.)

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Chapter1: Functions And Models
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**Problem 6: Applying Newton's Method**

**Objective:** 
Apply Newton's method twice to approximate the cube root of 3, denoted as \(3^{1/3}\).

**Instructions:**
- **Initial Approximation:** Begin with \(x_0 = 3\).
- Find the subsequent approximations \(x_1\) and \(x_2\) using Newton's method.

**Explanation:**

Newton's method is an iterative technique for finding successively better approximations to the roots (or zeroes) of a real-valued function. The general formula for Newton’s iteration is:

\[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \]

For the cube root approximation, we define the function:

\[ f(x) = x^3 - 3 \]

The derivative of this function is:

\[ f'(x) = 3x^2 \]

With these, you can apply the Newton’s iteration to find \(x_1\) and \(x_2\).
Transcribed Image Text:**Problem 6: Applying Newton's Method** **Objective:** Apply Newton's method twice to approximate the cube root of 3, denoted as \(3^{1/3}\). **Instructions:** - **Initial Approximation:** Begin with \(x_0 = 3\). - Find the subsequent approximations \(x_1\) and \(x_2\) using Newton's method. **Explanation:** Newton's method is an iterative technique for finding successively better approximations to the roots (or zeroes) of a real-valued function. The general formula for Newton’s iteration is: \[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \] For the cube root approximation, we define the function: \[ f(x) = x^3 - 3 \] The derivative of this function is: \[ f'(x) = 3x^2 \] With these, you can apply the Newton’s iteration to find \(x_1\) and \(x_2\).
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