Apply L'Hôpital's Rule to evaluate the following limit. It may be necessary to apply it more than once. lim (cos x) cs I→0 CSC I =

Q: sin4x lim x→0+ 5x 6. Find the one-sided limit (if it exists).

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Q: 2 ež h(x) 1 - 4 What is lim h(x)? x→+∞

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Q: Let s(x)=sin(x)/x. Explain why it is true that Lim (X-> 2pi) s(x)=0

A: Let  sx=sinxx Explain why it is true that limx→2πsx=0

Q: Evaluate the following: Lim(x to 0) (1+x-cosx-sinx)/(x+cosx-sinx-1)

A: This question is related to limit.

Q: show that the lim dose not exist x.y-00

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Q: find the following limits if exist:- limx-0 1-cosx x sinx

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Q: Evaluate the following limits: 1-sinx a. lim X→n1-cosx x²-49 b. lim x→7 x-7 C. lim X00 x2+1

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