Apply Fourier transform, jw F(w) = F₁ (w) + F₂ (w)...... equation 2 |F₁(t) = −8(t + 2) + 6(t-2)........ equation 3 now t replace by w, ejw te-jw F₁(w) = -2 2 سلام F₁(w) = -4 1(w) = 4jwSin²w. and -e 2 x 2 How did he get the value inside the circle
Apply Fourier transform, jw F(w) = F₁ (w) + F₂ (w)...... equation 2 |F₁(t) = −8(t + 2) + 6(t-2)........ equation 3 now t replace by w, ejw te-jw F₁(w) = -2 2 سلام F₁(w) = -4 1(w) = 4jwSin²w. and -e 2 x 2 How did he get the value inside the circle
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Apply Fourier transform,
|jw F(w) = F₁ (w) + F₂(w)...... equation 2
F₁ (t) = −8(t + 2) + d(t− 2)........ equation 3
now t replace by w,
eju te jw
F₁(w) = -2[+]x2
F₁ (w) = -4 [ee]
2
1₁(w) = 4jwSin²w.
and
How did he get the
value inside the circle](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffcb0d60-4230-457f-8d09-a661b8110265%2F71137299-3619-4273-83b1-959f514176cb%2F92v4nd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Apply Fourier transform,
|jw F(w) = F₁ (w) + F₂(w)...... equation 2
F₁ (t) = −8(t + 2) + d(t− 2)........ equation 3
now t replace by w,
eju te jw
F₁(w) = -2[+]x2
F₁ (w) = -4 [ee]
2
1₁(w) = 4jwSin²w.
and
How did he get the
value inside the circle
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