APPLICATIONS 225 To begin, we note that the gamma function is the solution to the difference equation Ak+1 = kak. (7.80) This follows directly from the results of Section 2.4. To determine the dom- inant or leading behavior of the solution to equation (7.80), we rewrite it in the form ak = eSk (7.81) Substitution of equation (7.81) into (7.80) gives Sk+1 - Sk = ln k, (7.82) whose exact solution is k-1 Sk = S1 + Σhr. (7.83) r=1 Since our interest is in k → ∞, the dominant behavior of Sk can be calculated by approximating the sum by an integral; therefore, In t dt ~ k In k. (7.84) Consequently, ar takes the form ak = k*bk, (7.85) where br is an unknown function whose dominant behavior will now be de- termined. To do this, we substitute equation (7.85) into equation (7.80) and obtain -(k+1) (1+ ) bk+1 = (7.86) Using the fact that lim (1+ h)'/h = e, (7.87) it follows that -(k+1) 1 (1+) lim (7.88) and for k → ∞, we have (). bk+1 ~ (7.89) Thus, the dominant behavior of br is given by the expression br ~ e-k (7.90) If we now set br = e¬kCk; (7.91)
APPLICATIONS 225 To begin, we note that the gamma function is the solution to the difference equation Ak+1 = kak. (7.80) This follows directly from the results of Section 2.4. To determine the dom- inant or leading behavior of the solution to equation (7.80), we rewrite it in the form ak = eSk (7.81) Substitution of equation (7.81) into (7.80) gives Sk+1 - Sk = ln k, (7.82) whose exact solution is k-1 Sk = S1 + Σhr. (7.83) r=1 Since our interest is in k → ∞, the dominant behavior of Sk can be calculated by approximating the sum by an integral; therefore, In t dt ~ k In k. (7.84) Consequently, ar takes the form ak = k*bk, (7.85) where br is an unknown function whose dominant behavior will now be de- termined. To do this, we substitute equation (7.85) into equation (7.80) and obtain -(k+1) (1+ ) bk+1 = (7.86) Using the fact that lim (1+ h)'/h = e, (7.87) it follows that -(k+1) 1 (1+) lim (7.88) and for k → ∞, we have (). bk+1 ~ (7.89) Thus, the dominant behavior of br is given by the expression br ~ e-k (7.90) If we now set br = e¬kCk; (7.91)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Topic Video
Question
Explain the determine yellow
![ences (World Scientific, Singapore, 2004), Chapter 7.
7.2.4
Approximating Factorials
For integer k, the gamma function reduces to the factorial expression
T(k)
(k – 1)!.
(7.77)
Of great interest for many calculations in applied mathematics, the sciences,
and engineering is the representation of the factorial for large values of k.
This corresponds to k → , and such a representation is called an asymptotic
expansion. For equation (7.77), the asymptotic expansion is
2T
k
T(k) = (k – 1)! ~
k
A1
1+
k
A1
k2
Аз
+..
k3
(7.78)
where the symbol “n" will mean "k → oo." In this equation, the constants
A1, A2, and A3 are
1
Aj =
12'
1
A2 =
288
139
A3 =
(7.79)
51, 840
The above expansion is called the Stirling series.
We now derive equation (7.78) except for an overall multiplicative con-
stant.
APPLICATIONS
225
To begin, we note that the gamma function is the solution to the difference
equation
ak+1 = kak.
(7.80)
This follows directly from the results of Section 2.4. To determine the dom-
inant or leading behavior of the solution to equation (7.80), we rewrite it in
the form
ak = eSk
(7.81)
Substitution of equation (7.81) into (7.80) gives
Sk+1 – Sk = In k,
(7.82)
whose exact solution is
k-1
Sk = S1 +> Inr.
(7.83)
r=1
Since our interest is in k →x, the dominant behavior of Sk can be calculated
by approximating the sum by an integral; therefore,
Sk -
In t dt ~ k In k.
(7.84)
Consequently, ak takes the form
k* bk,
(7.85)
ak =
where br is an unknown function whose dominant behavior will now be de-
termined. To do this, we substitute equation (7.85) into equation (7.80) and
obtain
-(k+1)
1
bk+1 =
1+-
br.
(7.86)
(†+)--
Using the fact that
lim (1+ h)'/h = e,
(7.87)
it follows that
-(k+1)
1
1
lim
1+
(7.88)
e
and for k → ∞, we have
bk+1 ~
bk.
(7.89)
Thus, the dominant behavior of br is given by the expression
bk ~e-k.
(7.90)
If we now set
br = e-kck
(7.91)
Ck;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48dbf4e2-6a0f-454b-99ed-fcbc11bc7c27%2F4eab4e03-fb03-43b1-9947-93ec87a42814%2Fa8thik_processed.png&w=3840&q=75)
Transcribed Image Text:ences (World Scientific, Singapore, 2004), Chapter 7.
7.2.4
Approximating Factorials
For integer k, the gamma function reduces to the factorial expression
T(k)
(k – 1)!.
(7.77)
Of great interest for many calculations in applied mathematics, the sciences,
and engineering is the representation of the factorial for large values of k.
This corresponds to k → , and such a representation is called an asymptotic
expansion. For equation (7.77), the asymptotic expansion is
2T
k
T(k) = (k – 1)! ~
k
A1
1+
k
A1
k2
Аз
+..
k3
(7.78)
where the symbol “n" will mean "k → oo." In this equation, the constants
A1, A2, and A3 are
1
Aj =
12'
1
A2 =
288
139
A3 =
(7.79)
51, 840
The above expansion is called the Stirling series.
We now derive equation (7.78) except for an overall multiplicative con-
stant.
APPLICATIONS
225
To begin, we note that the gamma function is the solution to the difference
equation
ak+1 = kak.
(7.80)
This follows directly from the results of Section 2.4. To determine the dom-
inant or leading behavior of the solution to equation (7.80), we rewrite it in
the form
ak = eSk
(7.81)
Substitution of equation (7.81) into (7.80) gives
Sk+1 – Sk = In k,
(7.82)
whose exact solution is
k-1
Sk = S1 +> Inr.
(7.83)
r=1
Since our interest is in k →x, the dominant behavior of Sk can be calculated
by approximating the sum by an integral; therefore,
Sk -
In t dt ~ k In k.
(7.84)
Consequently, ak takes the form
k* bk,
(7.85)
ak =
where br is an unknown function whose dominant behavior will now be de-
termined. To do this, we substitute equation (7.85) into equation (7.80) and
obtain
-(k+1)
1
bk+1 =
1+-
br.
(7.86)
(†+)--
Using the fact that
lim (1+ h)'/h = e,
(7.87)
it follows that
-(k+1)
1
1
lim
1+
(7.88)
e
and for k → ∞, we have
bk+1 ~
bk.
(7.89)
Thus, the dominant behavior of br is given by the expression
bk ~e-k.
(7.90)
If we now set
br = e-kck
(7.91)
Ck;
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