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apacitols ifferent dielectrics inside. The conducting plates will be made from aluminum (with surface area A). he first capacitor uses a plane of glass with thickness d, surface area A, and dielectric constant x Figure 1). It has capacitance Colass: The second uses a piece of plastic with thickness d/2, surface Figure 1 rea A, and dielectric constant 1.5K (Figure 2). It has capacitance Cplastic: The third one uses both lass and plastic, and is shown in Figure 3. This configuration has capacitance Ctotal- Figure 2 1.5 K Figure 3 (a) Enter an expression for the theoretical capacitance, Colass, of the setup using only glass (Figure 1) in terms of A, d, K, and ɛ0. "glass = B 80 7 8 HOME K 4 6. Celass 1 3 A h j + - END P VO BACKSPACE DEL CLEAR m (b) Now enter an expression for the capacitance using only plastic, Cplastic, in terms of the capacitance using only glass, Calass- (c) Now you construct the last capacitor, using both plastic and glass, with no gap between the glass and plastic. Enter an expression for the pacitance of this system, Ctotal, in terms of A, d, K, and ɛ0. (d) Calculate the capacitance of the final system, Ctotal, in nanofarads, assuming A = 7.95 cm2, d= 0.45 mm, K = 3.1.

apacitols ifferent dielectrics inside. The conducting plates will be made from aluminum (with surface area A). he first capacitor uses a plane of glass with thickness d, surface area A, and dielectric constant x Figure 1). It has capacitance Colass: The second uses a piece of plastic with thickness d/2, surface Figure 1 rea A, and dielectric constant 1.5K (Figure 2). It has capacitance Cplastic: The third one uses both lass and plastic, and is shown in Figure 3. This configuration has capacitance Ctotal- Figure 2 1.5 K Figure 3 (a) Enter an expression for the theoretical capacitance, Colass, of the setup using only glass (Figure 1) in terms of A, d, K, and ɛ0. "glass = B 80 7 8 HOME K 4 6. Celass 1 3 A h j + - END P VO BACKSPACE DEL CLEAR m (b) Now enter an expression for the capacitance using only plastic, Cplastic, in terms of the capacitance using only glass, Calass- (c) Now you construct the last capacitor, using both plastic and glass, with no gap between the glass and plastic. Enter an expression for the pacitance of this system, Ctotal, in terms of A, d, K, and ɛ0. (d) Calculate the capacitance of the final system, Ctotal, in nanofarads, assuming A = 7.95 cm2, d= 0.45 mm, K = 3.1.

College Physics
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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As part of a science fair project you want to construct several capacitors with different dielectrics inside. The conducting plates will be made from aluminum (with surface area A). The first capacitor uses a plane of glass with thickness d, surface area A, and dielectric constant K (Figure 1). It has capacitance Cglass- The second uses a piece of plastic with thickness d/2, surface Figure 1 area A, and dielectric constant 1.5K (Figure 2). It has capacitance Cplastic- The third one uses both glass and plastic, and is shown in Figure 3. This configuration has capacitance Ctotal- Figure 2 1.5 Figure 3 1.5 K (a) Enter an expression for the theoretical capacitance, Cglass, of the setup using only glass (Figure 1) in terms of A, d, K, and ɛ0. Cglass 7 8 НOME K 4 5 А Cglass d 1 2 3 h + END - P VO BACKSPACE CLEAR DEL (b) Now enter an expression for the capacitance using only plastic, Cplastic, in terms of the capacitance using only glass, Cglass- (c) Now you construct the last capacitor, using both plastic and glass, with no gap between the glass and plastic. Enter an expression for the capacitance of this system, Ctotal, in terms of A, d, k, and ɛ0. (d) Calculate the capacitance of the final system, Ctotal, in nanofarads, assuming A = 7.95 cm², d= 0.45 mm, K = 3.1.
Transcribed Image Text:As part of a science fair project you want to construct several capacitors with different dielectrics inside. The conducting plates will be made from aluminum (with surface area A). The first capacitor uses a plane of glass with thickness d, surface area A, and dielectric constant K (Figure 1). It has capacitance Cglass- The second uses a piece of plastic with thickness d/2, surface Figure 1 area A, and dielectric constant 1.5K (Figure 2). It has capacitance Cplastic- The third one uses both glass and plastic, and is shown in Figure 3. This configuration has capacitance Ctotal- Figure 2 1.5 Figure 3 1.5 K (a) Enter an expression for the theoretical capacitance, Cglass, of the setup using only glass (Figure 1) in terms of A, d, K, and ɛ0. Cglass 7 8 НOME K 4 5 А Cglass d 1 2 3 h + END - P VO BACKSPACE CLEAR DEL (b) Now enter an expression for the capacitance using only plastic, Cplastic, in terms of the capacitance using only glass, Cglass- (c) Now you construct the last capacitor, using both plastic and glass, with no gap between the glass and plastic. Enter an expression for the capacitance of this system, Ctotal, in terms of A, d, k, and ɛ0. (d) Calculate the capacitance of the final system, Ctotal, in nanofarads, assuming A = 7.95 cm², d= 0.45 mm, K = 3.1.
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