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AP 1. rv²v+v²v-(r + 1)v==(r²-r+r²²-r²), at r = 6, v = 0 2µL

AP 1. rv²v+v²v-(r + 1)v==(r²-r+r²²-r²), at r = 6, v = 0 2µL

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve this de item 1 only
ΔΡ 1. rrv+rv-(r+ 1)v =-(v²-r+riv-P),atr=6,v = 0 24µL 2. (2ty + 16r + 4y + 32) dz + (3xy - 9y – 7x +21)dy = 0,y (5) = -6
Transcribed Image Text:ΔΡ 1. rrv+rv-(r+ 1)v =-(v²-r+riv-P),atr=6,v = 0 24µL 2. (2ty + 16r + 4y + 32) dz + (3xy - 9y – 7x +21)dy = 0,y (5) = -6
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