Anystate Auto Insurance Company took a random sample of 352 insurance claims paid out during a 1-year period. The average claim paid was $1575. Assume a = $236. Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit upper limit 2$ Find a 0.99 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit upper limit %24 Need Help? Read It

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: A newsagent wants to estimate the total retail value of the 963 birthday cards it has in its…

A: Given that  Sample Mean \bar XXˉ = 3.433.43 Sample Standard Deviation (s)(s) = 0.380.38…

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

A:

Q: f n=450 and X = 360, construct a 99% confidence interval.

A:

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A: Thus, sample mean = 40. Sample standard deviation, s is 15. The sample size, n is 18. The degrees of…

Q: Believe it or not, there are some people who dont think that Duke will win the NCAA tournament this…

A: Obtain the 90% Confidence Interval for the IQ of DDs.   The 90% Confidence Interval for the IQ of…

Q: You want to purchase a used car. The mean monthly payment for a random sample of 12 cars advertised…

A: Given: n=12x¯=275σ=35 Confidence level = 95%

Q: A sample of 47 Charleston County households have a mean income of $32,346 with a standard deviation…

A: The sample size is 47, sample mean is $32346, and sample standard deviation is $8571. The confidence…

Q: Noise levels at various area urban hospitals were measured in decibels. The mean of the noise levels…

A: Interval estimation is proposed as an estimate of the unknown parameter. Confidence interval is also…

Q: Find the condence level and a for a. a 90% confidence interval.b. a 99% confidence interval.

A: a.The confidence level and α for a 90% confidence interval is obtained below:The confidence level is…

Q: Anystate Auto Insurance Company took a random sample of 354 insurance claims paid out during a…

A: Given: n = 354 X = 1590 σ = 238 Formula Used: Confidende interval = X ± Z*σn

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: GROUP 2 You work for a consumer advocate ogency and want to find the mean repair cost of a washing…

A: According to the provided information, Mean (x̅) = 100 Standard deviation (σ) = 17.50 Sample size…

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: A confidence interval is an interval that is used to estimate the unknown parameter. The lowest…

Q: If n 28, = 37, and s = 6.2, construct a confidence interval at a 97% confidence level. Assume the…

A: Solution: The following information is given to us: s=6.2 n =28 A 97% confidence interval is…

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that sample mean is 50 and standard deviation is 12.

Q: n a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=25Mean(x)=38standard deviation(s)=19confidence interval(c)=98%

Q: working for financial companies in New York City receive large bonuses at the end of the year. A…

A: As the population standard deviation is not known, we will t-distribution. The degrees of freedom…

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

A: Solution: Let X be the per capita income. From the given information, x-bar = $31.7, n=753 and σ=$9.…

Q: In a survey, 12 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean (x̄) = $ 30, standard deviation        (s) = $ 8 and sample size (n) = 12 Then,  We will…

Q: Anystate Auto Insurance Company took a random sample of 372 insurance claims paid out during a…

A:

Q: feeling more enriched. For some reason that she can't quite figure out, most people don't believe…

A: Given Data Sample Size, n = 64 Number of successes, x = 34.0 Significance level,…

Q: Alan wants to estimate the proportion of adults who walk to work. In a survey of 10 adults, he finds…

A: Given: Alan wants to estimate the proportion of adults who walk to work. Total number of adults=10…

Q: We would like to create a confidence interval for the mean. Which of the following would produce the…

A: Margin of error = Width/2

Q: Anystate Auto Insurance Company took a random sample of 372 insurance claims paid out during a…

A: Sample size (n) = 372Sample mean () = 1545Standard deviations () = 270

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: Solution: Let X be the amount spent. From the given information, x-bar=$36, n=14 and S=$16.

Q: Suppose you needed to form a 92% confidence interval for a population mean. What z value would you…

A:

Q: According to a poll, 79% of California adults (398 out of 506 surveyed) feel that education is one…

A: Proportion of adult feel that education is one of the top issues facing California = 79%= 0.79Sample…

Q: uppose you calculate a 99% confidence interval of 14.1 to 21.84. Determine the margin of error.

A:

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: Given that, x¯=32,s=8,n=21 The degree of freedom is, df=n-1   =21-1   =20 Critical value: Using the…

Q: You are a researcher studying the antler size of male Alaskan Moose in a certain Alaska location.…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.