ant augmentation rhinoplasty is used to al properties of the human nasal periost (%) was 26.0, and the standard deviat ssuming a normal distribution for failur bility. (Use a 95% confidence interval. R %, | %) redict the strain for a single adult in a w answers to two decimal places.)

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends on various
biomechanical properties of the human nasal periosteum and fascia. An article reported that for a sample of 17 (newly deceased) adults, the mean
failure strain (%) was 26.0, and the standard deviation was 3.1.
(a) Assuming a normal distribution for failure strain, estimate true average strain in a way that conveys information about precision and
reliability. (Use a 95% confidence interval. Round your answers to two decimal places.)
%,
%
(b) Predict the strain for a single adult in a way that conveys information about precision and reliability. (Use a 95% prediction interval. Round
your answers to two decimal places.)
%,
How does the prediction compare to the estimate calculated in part (a)?
O The prediction interval is the same as the confidence interval in part (a).
The prediction interval is much wider than the confidence interval in part (a).
The prediction interval is much narrower than the confidence interval in part (a).
You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends on various biomechanical properties of the human nasal periosteum and fascia. An article reported that for a sample of 17 (newly deceased) adults, the mean failure strain (%) was 26.0, and the standard deviation was 3.1. (a) Assuming a normal distribution for failure strain, estimate true average strain in a way that conveys information about precision and reliability. (Use a 95% confidence interval. Round your answers to two decimal places.) %, % (b) Predict the strain for a single adult in a way that conveys information about precision and reliability. (Use a 95% prediction interval. Round your answers to two decimal places.) %, How does the prediction compare to the estimate calculated in part (a)? O The prediction interval is the same as the confidence interval in part (a). The prediction interval is much wider than the confidence interval in part (a). The prediction interval is much narrower than the confidence interval in part (a). You may need to use the appropriate table in the Appendix of Tables to answer this question.
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