Answers:(a) If P = 470 N,Ax =Ay=Ex = iNPmaxNN(b) The maximum value which P may have forstatic equilibrium:N (a) Determine the reactions at A and E if P =470 N. The reactions are positive if to the rightor up, negative if to the left or down.(b) What is the maximum value which P mayhave for static equilibrium? Neglect the weightof the structure compared with the appliedloads.3.1 mE4.5 mB31 3290 ND4.5 mP

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Answered: Answers: (a) If P = 470 N, Ax = Ay= Ex…

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Answers: (a) If P = 470 N, Ax = Ay= Ex = i N Pmax N N (b) The maximum value which P may have for static equilibrium: N

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

Answers:
(a) If P = 470 N,
Ax =
Ay=
Ex = i
N
Pmax
N
N
(b) The maximum value which P may have for
static equilibrium:
N

(a) Determine the reactions at A and E if P =
470 N. The reactions are positive if to the right
or up, negative if to the left or down.
(b) What is the maximum value which P may
have for static equilibrium? Neglect the weight
of the structure compared with the applied
loads.
3.1 m
E
4.5 m
B
31 3290 N
D
4.5 m
P

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