Answer the questions below about the highlighted atom in this Lewis structure: н :0: н—с —с—о —н H In how many sigma bonds does the highlighted atom participate? In how many pi bonds does the highlighted atom participate? U ? What is the orbital hybridization of the highlighted atom?

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### Understanding Lewis Structures: Example 2

In this section, we will answer questions regarding the highlighted atom in a Lewis structure of an organic compound.

__Lewis Structure:__

The molecule shown is an organic compound where the Lewis structure is given. It consists of three hydrogen atoms (H), two carbon atoms (C), and one oxygen atom (O). Here’s the specific arrangement in the structure:

```
       H       :O:
       |       || 
H—C—C—O—H
    |         ..
    H
```

The oxygen atom connected to one of the carbon atoms is highlighted in red. It is bonded to the adjacent carbon atom with a double bond and has two lone pairs of electrons.

__Questions:__

In this example, we will specifically address the following questions related to the highlighted oxygen atom:

1. **In how many sigma bonds does the highlighted atom participate (σ)?**
2. **In how many pi bonds does the highlighted atom participate (π)?**
3. **What is the orbital hybridization of the highlighted atom?**

Use the graphical interface provided to answer these:

| Question                                                    | Answer        |
|---------------------------------------------------------|---------------|
| In how many sigma bonds does the highlighted atom participate? | [Answer Box]  |
| In how many pi bonds does the highlighted atom participate?  | [Answer Box]  |
| What is the orbital hybridization of the highlighted atom?   | [Answer Box]  |

__Graph and Check Tools:__

To the right, there is a tool for checking your answers with icons for confirming answers (checkmark), an option to redo the process (curved arrow), and access help (question mark).

---

This activity helps you practice identifying bonding types and understanding the geometric and electronic structure of molecules through Lewis structures. Use the Lewis structure to determine the number and types of bonds, as well as the hybridization state of the highlighted atom.
Transcribed Image Text:### Understanding Lewis Structures: Example 2 In this section, we will answer questions regarding the highlighted atom in a Lewis structure of an organic compound. __Lewis Structure:__ The molecule shown is an organic compound where the Lewis structure is given. It consists of three hydrogen atoms (H), two carbon atoms (C), and one oxygen atom (O). Here’s the specific arrangement in the structure: ``` H :O: | || H—C—C—O—H | .. H ``` The oxygen atom connected to one of the carbon atoms is highlighted in red. It is bonded to the adjacent carbon atom with a double bond and has two lone pairs of electrons. __Questions:__ In this example, we will specifically address the following questions related to the highlighted oxygen atom: 1. **In how many sigma bonds does the highlighted atom participate (σ)?** 2. **In how many pi bonds does the highlighted atom participate (π)?** 3. **What is the orbital hybridization of the highlighted atom?** Use the graphical interface provided to answer these: | Question | Answer | |---------------------------------------------------------|---------------| | In how many sigma bonds does the highlighted atom participate? | [Answer Box] | | In how many pi bonds does the highlighted atom participate? | [Answer Box] | | What is the orbital hybridization of the highlighted atom? | [Answer Box] | __Graph and Check Tools:__ To the right, there is a tool for checking your answers with icons for confirming answers (checkmark), an option to redo the process (curved arrow), and access help (question mark). --- This activity helps you practice identifying bonding types and understanding the geometric and electronic structure of molecules through Lewis structures. Use the Lewis structure to determine the number and types of bonds, as well as the hybridization state of the highlighted atom.
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