Answer the question based on the node structure shown below. There are two different node structures. Class fields are shown below.There is a head showing the first student in the list.Class NodeStudent{ public Student value, public NodeStudent next, public NodeCourse nextCourse ..}Class NodeCourse{public Course value, public NodeCourse next.}Class Student{ public String name, public string surname public string department ..}Class Course{public string name, public int midterm, public int final.}Ayse Bilir EndistriFiek s0 60Matematik 70 89Tarih 70 90Fizk 30 4sT. Dso 85Matematik 50 60Kimyaso soa) Write a method that will display the name, last name and the average of students of a given department. There is a head showingthe first student in the list.b) sort the list based on given course's grades. For example if the name of the course is Fizik then the list should be sorted by Fizikgrades. You can use any sorting method you like withoout using any structure like array, arraylist etc.

We can see in the node structure that there are 2 types of marks given. I have written a python code…

Answered: Answer the question based on the node…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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After a tuple is created, its items can be changed. True False A tuple's items can be access by square brackets, similar to lists. True False
Lab Goal : This lab was designed to teach you more about list processing and algorithms.Lab Description : Write a program that will search a list to find the first odd number. If an odd number is found, then find the first even number following the odd number. Return the distance between the first odd number and the LAST even number. Return -1 if no odd numbers are found or there are no even numbers following an odd number
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Background: When searching for an item in a list, each item that we examine (compare) is considered to be interrogated. If we search for John, the following names are interrogated: Harry, Larry, John (in that order). If two names tie for the middle position, choose the first of the two names for the middle.If we search this same list for John using the Sequential search we would interrogate all the names from Alice through John. We would start with Alice, move to Bob, move to Carol and so forth until we reached John. Directions: Use the original list of names (Alice - Oliver) to answers questions 1-8. Using a sequential search, what names are interrogated to find Carol? Using a sequential search, what names are interrogated to determine that Sam is not in the list? Using a binary search, what names are interrogated to find Carol? Using a binary search, what names are interrogated to determine that Sam is not in the list? Will a binary search or sequential search find Alice…
Write a program that animates the linear search algorithm. Create a list that consists of 20 distinct numbers from 1 to 20 in a random order. The elements are displayed in a histogram, as shown in Figure 10.17. You need to enter a search key in the text field. Clicking the Step button causes the program to perform one comparison in the algorithm and repaints the histogram with a bar indicating the search position. When the algorithm is finished, display a dialog box to inform the user. Clicking the Reset button creates a new random list for a new start.
Use € Or € to indicate whether the given object 1s an element of the given set.5 {1,2,3,4,5,6}
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }
The numbers on the left margin denote line numbers. line#01 class LL_node {02 int val;03 LL_node next;04 public LL_node (int n) {05 val = n;06 next = null;07 }08 public void set_next (LL_node nextNode) {09 next = nextNode;10 }11 public LL_node get_next () {12 return next;13 }14 public void set_value (int input) {15 val = input;16 }17 public int get_value () {18 return val;19 }20 }21 public class LL {22 protected LL_node head;23 protected LL_node tail;24 public LL () {25 head = null;26 tail = null;27 }28 public int append (int n) {29 if (head == null) {30 head = new LL_node(n);31 tail = head;32 } else {33 LL_node new_node;34 new_node = new LL_node(n);35 tail.set_next (new_node);36 tail = new_node;37 }38 return n;39 }40 } which the following statement…
The ListInterface defines two constructors.
3.)Declare variables a. The images variable containing an HTML collection of all elements with the tag name "img". b. The photoBucket variable referencing the element with the id "photo_bucket". c. The photoList variable referencing the element with the id "photo_list". 4.) Create a for loop that iterates through all of the items in the images collection. 5.) Within the for loop insert an onclick event handler that runs an anonymous function when an image is clicked. 6.) When an image is clicked it is either moved from the photo bucket to the photo list or from the photo list back to the photo bucket. To determine which action to perform, add the following if else statement to the anonymous function: a. If the parent element of the clicked image has an id equal to "photo_bucket" then do the following: (i) Create an element node named newltem for the li element, (ii) append newltem to the photoList object, and (i) append the image to the newltem object using the appendChild() method.…
Lab Goal : This lab was designed to teach you more about list processing and algorithms.Lab Description : Write a program that will search through a list to find the smallest number and the largest number. The program will return the average the largest and smallest numbers. You must combine variables, ifs, and a loop to create a working method. There will always be at least one item in the list.
When we use the Group-Object cmdlet, it will create this new property, which displays the number of objects in each grouping: Group of answer choices Number Count Entry Name

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Answer the question based on the node structure shown below. There are two different node structures. Class fields are shown below. There is a head showing the first student in the list.