Answer the given question with a proper explanation and step-by-step solution. LC-3 Assembly Language: Would my code using bit-shift work for dividing by a thousand or do is there something wrong with it? I plan to use it to connect to a bunch of subroutines.
Answer the given question with a proper explanation and step-by-step solution. LC-3 Assembly Language: Would my code using bit-shift work for dividing by a thousand or do is there something wrong with it? I plan to use it to connect to a bunch of subroutines.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Answer the given question with a proper explanation and step-by-step solution.
LC-3 Assembly Language: Would my code using bit-shift work for dividing by a thousand or do is there something wrong with it?
I plan to use it to connect to a bunch of subroutines.
![DIVLOOP1000
LD R4, DIVTHOU; Load Negative 1000 in R4 since we are using it divide by
; FILLS
ADD R3, R2, R4; R2 will be the value incrementing by one
BRZp DIVEND; Skip all if it is zero or positive
LD R3, HOLDER; Load Holder into R3
AND R3, R3, R1; AND R3 and R1, store back into R3
BRZ #3; If result zero, move down 3
ADD R1, R1, R1; ADD R1 by itself
ADD R1, R1, #1; ADD one to remove the remainder
BRnzp #1 Skip next line.
ADD R1, R1, R1; ADD R1 by itself without adding one
DIVEND
ADD R2, R2, #1; ADD one to R2 until done
BRnzp DIVLOOP1000; Go back to loop
DIVTHOU
DIVHUN
DIVTEN
DIVONE
HOLDER
NEWNUM
SKIPY
ST R1, NEWNUM
BRnzp SKIPY
SAVEZ FILL #0
SAVEO FILL #0
SAVET .FILL #0
SAVEH .FILL #0
SAVEF .FILL #0
SAVEI FILL #0
SAVES .FILL #0
. FILL
. FILL
. FILL #-10
. FILL #-1
. FILL b1000000000000000
.BLKW 1
#-1000
#-100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff422c3b3-bfd6-4947-a5c6-59c8d9b398a1%2Fab8b8cdc-41b5-4ed2-a9ab-47a08b6b5ccc%2Fetcrxktl_processed.png&w=3840&q=75)
Transcribed Image Text:DIVLOOP1000
LD R4, DIVTHOU; Load Negative 1000 in R4 since we are using it divide by
; FILLS
ADD R3, R2, R4; R2 will be the value incrementing by one
BRZp DIVEND; Skip all if it is zero or positive
LD R3, HOLDER; Load Holder into R3
AND R3, R3, R1; AND R3 and R1, store back into R3
BRZ #3; If result zero, move down 3
ADD R1, R1, R1; ADD R1 by itself
ADD R1, R1, #1; ADD one to remove the remainder
BRnzp #1 Skip next line.
ADD R1, R1, R1; ADD R1 by itself without adding one
DIVEND
ADD R2, R2, #1; ADD one to R2 until done
BRnzp DIVLOOP1000; Go back to loop
DIVTHOU
DIVHUN
DIVTEN
DIVONE
HOLDER
NEWNUM
SKIPY
ST R1, NEWNUM
BRnzp SKIPY
SAVEZ FILL #0
SAVEO FILL #0
SAVET .FILL #0
SAVEH .FILL #0
SAVEF .FILL #0
SAVEI FILL #0
SAVES .FILL #0
. FILL
. FILL
. FILL #-10
. FILL #-1
. FILL b1000000000000000
.BLKW 1
#-1000
#-100
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