Answer the following within 10-5.ive inserted the method that being used in this problem please use the same method based on the image i inserted2. Use Newton-Raphson method to solve x - cos x = 0, [0, π/2]. Newdon Raphson Methodtxample: Solve thc equationTable:Iteration3.0000C 3154w/ rool in the interval (3,5](in 4 decimal places)f(x):0C. 31545. 41414. 1SI6y=fu)5. 41414.751634.2011Solution : initialvaluc = 34.20113.8879.86873.74793.7479f(x)fa) = e-6x=e- 3x= oPoPi3-73333-73333. 1331f (P.)3. 73313-73311f'(xa)IHerations3.00e3 -6 31543- ((3)4.31546:31543(+3154): 5.97416.3154 -e63154e5.434e3(5.4794)5.47415.4741==47516S 4741e-((5.4741)

We need to find the solution of x-cos(x)=0 in interval [0, π/2] using Newton-Raphson method (with…

Answer the following within 10-5. ive inserted the method that being used in this problem please use the same method based on the image i inserted 2. Use Newton-Raphson method to solve x - cos x = 0, [0, π/2]

Answer the following within 10-5. ive inserted the method that being used in this problem please use the same method based on the image i inserted 2. Use Newton-Raphson method to solve x - cos x = 0, [0, π/2]

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Answer the following within 10^-5.
ive inserted the method that being used in this problem please use the same method based on the image i inserted

2. Use Newton-Raphson method to solve x - cos x = 0, [0, π/2].

Newdon Raphson Method
txample: Solve thc equation
Table:
Iteration
3.0000
C 3154
w/ rool in the interval (3,5]
(in 4 decimal places)
f(x):0
C. 3154
5. 4141
4. 1SI6
y=fu)
5. 4141
4.7516
3
4.2011
Solution : initial
valuc = 3
4.2011
3.887
9.8687
3.7479
3.7479
f(x)
fa) = e-6x
=e- 3x= o
Po
Pi
3-7333
3-7333
3. 1331
f (P.)
3. 7331
3-73311
f'(xa)
IHerations
3.00
e
3 -
6 3154
3
- ((3)
4.3154
6:3154
3(+3154)
: 5.9741
6.3154 -e
63154
e
5.434
e
3(5.4794)
5.4741
5.4741=
=47516
S 4741
e
-((5.4741)

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