Answer the following questions. 1.  For the metal salt indicated in the procedure, you should use FeCl2.4H2O. Calculate the molar mass of this compound to 2 decimal places.  g/mol correct 1/1 2.  Your oxalate synthesis product will be FeC2O4.2H2O. Calculate the molar mass of this compound to 2 decimal places.  g/mol correct 1/1 3. Balance the molecular equation that shows your metal salt, FeCl2.4H2O, reacting with oxalic acid (H2C2O4) to form FeC2O4.2H2O (enter a 1 if a stoichiometric coefficient is one).

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Answer the following questions.
1.  For the metal salt indicated in the procedure, you should use FeCl2.4H2O. Calculate the molar mass of this compound to 2 decimal places.
 g/mol

correct 1/1


2.  Your oxalate synthesis product will be FeC2O4.2H2O. Calculate the molar mass of this compound to 2 decimal places.
 g/mol

correct 1/1


3. Balance the molecular equation that shows your metal salt, FeCl2.4H2O, reacting with oxalic acid (H2C2O4) to form FeC2O4.2H2O (enter a 1 if a stoichiometric coefficient is one).

      FeCl2.4H2O  +     H2C2O4  ⇒      FeC2O4.2H2O +      H2O  +     HCl
correct, 1/1


4.  Pyrolysis of FeC2O4.2H2O will follow one of the following molecular equations. Balance each molecular equation,

a.     FeC2O4.2H2O +    O2 ⇒     FeO  +   H2O  +  CO2
 
b.     FeC2O4.2H2O +    O2 ⇒     Fe2O3  +   H2O  +  CO2
 
c.     FeC2O4.2H2           ⇒     FeCO3  +   H2O  +  CO
(a)correct, 1/1


(b)correct, 1/1


(c)correct, 1/1


5.  For pyrolysis reaction (4a) (above), calculate the theoretical yield (in grams) of the solid product, if you use 1.0 g FeC2O4.2H2O and that oxygen is the excess reactant
 g

correct 1/1


6.  For pyrolysis reaction (4b) (above), calculate the theoretical yield (in grams) of the solid product, if you use 1.0 g FeC2O4.2H2O and that oxygen is the excess reactant
 g

correct 1/1


7.  For pyrolysis reaction (4c) (above), calculate the theoretical yield (in grams) of the solid product, if you use 1.0 g FeC2O4.2H2O and that oxygen is the excess reactant
 g

correct 1/1


Complete the table below

Data Result
Mass of hydrated metal salt used 4.000 g
Volume of oxalic acid used (assume its concentration is, 4.000 g oxalic acid/50.00 mL soln) 50.00 mL
Mass of oxalic acid used 4.000 g
Mass of weigh dish + contents (after reaction) 3.983  g
Mass of empty weigh dish 1.881 g
Mass of filter paper 0.101 g
Actual yield of hydrated metal oxalate ppt (A)   g
Limiting reactant (B)           
Theoretical yield of hydrated metal oxalate product (C)    g
Percent yield of hydrated metal oxalte product (D)     %
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