Answer the fóllowing questions: |(a) If the crystal lattice constant for a metal is equal to (4.5 A), the type of crystal structure is Face centered cube, and the atomic weight equal to (25 g/m), when the temperature is equal to (900 °C); Calculate the following: 1. Diameter and density of the sodium, 2. Number of atoms in (1m³), 3. Density of free electrons if the material is trivalent. (b) For this metal; when the temperature is decreased below (900 oC); the crystal lattice type is changed from FCC to BCC, if we assumed that the radius of the atom is constant in both cases; calculate the density change.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Answer the following questions:
(a) If the crystal lattice constant for a metal is equal to (4.5•A), the type of crystal
structure is Face centered cube, and the atomic weight equal to (25 g/m),
when the temperature is equal to (900 °C); Calculate the following:
1. Diameter and density of the sodium,
2. Number of atoms in (1m³),
3. Density of free electrons if the material is trivalent.
(b) For this metal; when the temperature is decreased below (900 °C); the crystal
lattice type is changed from FCC to BCC, if we assumed that the radius of the
atom is constant in both cases; calculate the density change.
Transcribed Image Text:Answer the following questions: (a) If the crystal lattice constant for a metal is equal to (4.5•A), the type of crystal structure is Face centered cube, and the atomic weight equal to (25 g/m), when the temperature is equal to (900 °C); Calculate the following: 1. Diameter and density of the sodium, 2. Number of atoms in (1m³), 3. Density of free electrons if the material is trivalent. (b) For this metal; when the temperature is decreased below (900 °C); the crystal lattice type is changed from FCC to BCC, if we assumed that the radius of the atom is constant in both cases; calculate the density change.
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