Answer the following questions: Note: @m = Answer: πkô(1 + cos a) - - A) A 120 V, 1000 rpm, 6A separately excited DC motor has an armature resistance of 0.50. It is fed from a SP- SC-FWR with an input AC supply of single phase 280 V rms, and 60 Hz. If the triggering angle a = 55°, the no load speed of the motor is: Answer: rpm Ra T (ko)² B) If the triggering angle a = 150°, the no-load speed of the motor is: V rpm

Answer the following questions: Note: @m = Answer: πkô(1 + cos a) - - A) A 120 V, 1000 rpm, 6A separately excited DC motor has an armature resistance of 0.50. It is fed from a SP- SC-FWR with an input AC supply of single phase 280 V rms, and 60 Hz. If the triggering angle a = 55°, the no load speed of the motor is: Answer: rpm Ra T (ko)² B) If the triggering angle a = 150°, the no-load speed of the motor is: V rpm

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

To modeling separated excited DC motor by transfer function, you need to Trus Fuc block to get the represent armature current la field current If Speed Wr electromagnetic Torque Te *
The armature circuit of a free excited direct current motor with a nominal voltage of 600 V is fed from an adjusted direct voltage source. The excitation circuit is also powered from a regulated voltage source. It is used in an application that requires motor speed adjustment. The speed of the motor at the nominal armature voltage was measured as 1600 rpm. All losses of the motor and voltage source and the effect of armature reaction are neglected. It is accepted that the engine is not saturated.Answer the questions below.a) Draw the armature and excitation circuit of the motor and write the formulas for the equivalent circuit.b) If the load moment of the motor at the nominal armature voltage is 420 Nm, then calculate the armature current and the input power of the motor.c) If the armature voltage of the motor is kept constant at 600 V and the excitation current is decreased until the speed reaches 4000 rpm, then calculate the shaft moment. Show this working area on the M = f (W) axis.
A shunt DC motor is supplied by 520V terminals voltage and is used to supply a mechanical load with rotating speed of 1000rpm. The armature is wave-wound and has 500 conductors. The useful flux per pole is 0.03Wb and there are 4 poles (2 pairs of poles). The armature resistance is 0.4 Ohms. Calculate: 1.The internal emf of the motor. 2.The armature current. CLEAR AND CORRECT OR DISLIKE
Q5:- Adjust a fire angle for a three-phase fullwave semi-controlled converter to feed the separately exciter DC motor to get a load torque that can be reached to 730 rpm. When the supply voltage of converter is 160 volts per-phase and the absorbed current through the armature 40A with resistance 0.2 and a constant back emf 0.4v/rpm. Then find the maximum speed for motor assume the previous parameters values are a constant.
For a 18600W 2400rpm DC motor, the following values are given: Ra = 0.089 2 (value at room temperature (250C)), La = 0.00144 H, KT = 0.85 Nm / A and KV = 0.851 V / (rad / s)), (In calculations Use the hot resistance values at 1000C.) (Take the rated field winding losses as Wf= 210W.) If this DC machine is operating as a motor with rated flux at rated speed, calculate the rated torque (TR), rated current (IR), rated voltage (VR), efficiency (n) at the rated point, taking into account the winding losses. Find the speed (@NL) of this motor in no-load condition. TR Nm IR А VR V Eff = % ONL= rpm
A single phase Half wave AC voltage controller has a resistive load of 16 ohms with input supply voltage of 240 V, 50 Hz. The delay angle of the thyristors is, a = 21/5. Determine a) The rms output voltage and current. b) Input power factor and Input current. c) Average output voltage and current.
A DC motor should be operated in a strong field which is due to the What happens to if suddenly goes a) nothing, it continues rotating b) it over speeds c) it stops rotating current if moter if rotating to zero. as before
The supply voltage to a DC motor is 160V. If the back emf Ez=155V and the armature resistance A6 is 0.250, the armature current is a) 5A b) 10A c) 15A d) 20A 1800 ro/min The frequency
A 0,9 kW DC shunt motor is loaded by a constant torque of 12 Nm. The armature resistance of the motor is 5 Ω, and the field constant KØ = 3 Vs/rad. The motor is driven by a half wave thyristor converter. The power source is a 140 V, 50 Hz. The triggering angle of the converter is 450 and the conduction period is 1650 . Calculate the motor speed and the developed power.
(Qld) A three-phase 20-pole induction motor is rated at 800 V, 50 Hz. What is the synchronous speed of this machine if the voltage at its terminals is reduced to 400 V (a) 150 rpm, (b) 300 rpm, (c) 600 rpm, (d) 3000 rpm
A de machine is controlled by the step-down de-de converter shown below. The armature inductance La =0.2 mH and the armature resistance can be neglected. The armature current is 5A. The Buck converter is operating at the switching frequency is 30 kHz and the duty ratio is 0.8. L₁ + Answer the following questions: 1) Calculate the input voltage (Va) if the output voltage (ea = 200 V). 2) Find the ripple in the armature current (a). 3) Calculate the maximum and minimum values of the armature current (la). 4) Sketch the armature current (ia (t)) and the supply current (id (t)).
An armature controlled DC motor has the following parameters: Tf = 0.03 Nm KT = 0.15 Nm/A Imax = 2.4 A KĘ = 0.15 Vs/rad Wmax = 5000 rpm R = 0.8 Ohms 1. Determine the following: (i) The maximum output torque. (ii) The maximum power output. (iii) The maximum armature voltage. (iv) The no load motor speed when e = Emax 2. Plot the following relationships: (i) Torque versus current (ii) Induced voltage versus speed 3. If the above motor is operated at 3000 rpm with a load torque of 0.15 N.m, determine the armature voltage