Answer the following questions based on the C-V curve for an MOS capacitor shown in Fig. 5-39. The area of the capacitor is 104 μm². C(pF) A -1 FIGURE 5-39 B 0 с 0.5 [1] E 1 D QS C-V HF C-V Vg(V) (a) Is the substrate doping N type or P type? (b) What is the thickness of the oxide in the MOS capacitor? (c) What is the doping concentration of the substrate, Nsub? (d) What is the value of the capacitance at position C on the C-V curve shown above? (e) Sketch the energy band diagram of the MOS structure at positions A, B, C, D, and E on the C-V curve.

Answer the following questions based on the C-V curve for an MOS capacitor shown in Fig. 5-39. The area of the capacitor is 104 μm². C(pF) A -1 FIGURE 5-39 B 0 с 0.5 [1] E 1 D QS C-V HF C-V Vg(V) (a) Is the substrate doping N type or P type? (b) What is the thickness of the oxide in the MOS capacitor? (c) What is the doping concentration of the substrate, Nsub? (d) What is the value of the capacitance at position C on the C-V curve shown above? (e) Sketch the energy band diagram of the MOS structure at positions A, B, C, D, and E on the C-V curve.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A close analogy exists between the flow of energy by heat because of a temperature difference (see Section 19.6) and the flow of electric charge because of a potential difference. In a metal, energy dQ and electrical charge dq are both transported by free electrons. Consequently, a good electrical conductor is usually a good thermal conductor as well. Consider a thin conducting slab of thickness dx, area A, and electrical conductivity o, with a potential difference dVbetween opposite faces. (a) Show that the current I= dq| dt is given by the equation on the left: Charge conduction Thermal conduction da = GA dt dQ = kA dx dt dx In the analogous thermal conduction equation on the right (Eq. 19.17), the rate dQ/ dt of energy flow by heat (in SI units of joules per second) is due to a temperature gradient dT/ dx in a material of thermal conductivity k. (b) State analogous rules relating the direction of the electric current to the change in potential and relating the direction of energy…
QUESTION 2 A cylindrical nickel wire of radius 2.0 mm and length 1.6 m has a potential difference of 12 volts applied between its ends. If the wire carries a resistive load of 4.0 Q, what is the drift velocity of the conduction electrons in the wire? Assume that the number density of conduction electrons in the wire is 9.12 x 1028 conduction electrons/m3. a. 0.0060 mm/s b. 0.036 mm/s C. 0.046 mm/s d. 0.016 mm/s e. 0.026 mm/s