Answer the following problems.1. Independent random samples were selectedfrom two populations. The sample means, knownpopulation variance and sample sizes are given inthe following table:PopulatinnPopulation 2Sample mean38Population varianceSample size4046Find the 90% confidence interval for estimating thedifference in the population (- H2)

The two independent random samples selected from two populations. The given table is,…

Answered: Ánswer the following problems. 1.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 22 SAT scores are distributed with a mean of 1,500 and a standard deviation of 300. You are interested in estimating the average SAT score of first year students at your college. If you would like to limit the margin of error of your 95% confidence interval to 25 points, how many students should you sample? > Next Question hp Ce % & 3. 7 8 9 16 %24
Question 2 At the end of 2020, the mean age of the U.S. population was estimated to be 38.5 years old. You are tasked with determining whether the mean age of the population of IAT participants (for your chosen IAT data set) differs from the mean age of the U.S. population. 1. Let be the mean age of the population of IAT participants for your chosen IAT data set. State the hypotheses (symbolically and in words). Include a clear description of the populations and the variable. 2. 3. 4. Use StatCrunch to create a histogram for the age distribution in your unique IAT sample. Download the StatCrunch output window and embed your histogram with your response. Can we safely use the t-test with your IAT sample? Explain. Perform the t-test using StatCrunch. Copy the information from the StatCrunch output window and paste it into your response. Based on the P-value, state your conclusions in context. Use a 5% level of significance. (NOTE: Since StatCrunch correctly calculates the P-value for…
Question 6 In a random sample of 12 adults each of them ate 100 g of dark chocolate and in another random sample of 15 adults each of them ate 100 g of mik cho plasma antioxidant capacity was measured and the summary statistics are given below. Sample mean Sample standard deviation Dark chocolate (DC) Milk chocolate (MC) 171.5 6.8 165.0 7.2 At 5% significance level do the data provide sufficient evidence that dark chocolate produces different mean level of total blood plasmà antioxidant c Assume that the population distributions are normal with equal variance. a. The alternative hypothesis is H1: Pparkc (/ +) HMIKC b. The test statistic t= (round at two decimal places) c. The degrees of freedom (d.f.) = d. The critical value of the test = (do not round up). than the critical value, we (accept/reject) e. As the test statistic is (less/greater) produce different mean level of total blood plasma antioxidant capa that dark chocolate (does/does not) -tailed test. f. The above test is a…
The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. They would like the estimate to have a maximum error of 0.14 kWh. A previous study found that for an average family the variance is 4.84 kWh and the mean is 19.1 kWh per day. If they are using a 80% level of confidence, how large of a sample is required to estimate the mean usage of electricity? Question 8 options: 45 households 1959 households 949 housholds 405 households
Step 1 of 3. State the null and alternative hypotheses for the test. Step 2 of 3. Compute the value of the test statistic. Round your answer to three decimal places Step 3 of 3. Draw a conclusion and interpret the decision.
Q3: From the below Table, answer the following questions: NO Age Gender Salary 1001 20 1002 1003 22 30 1004 25 1005 34 1006 35 1007 38 1008 35 1009 30 M F F M F M F M 280 300 450 310 320 340 350 500 450 1)Trimmed mean 5% of age variable= 2) Interquartile Range of salary variable = 3) Variance of age variable = 4) Mean of salary variable = 5) represent the Gender variable by pie chart, showing the frequencies on it.
Question 4(a) A sample of test scores is obtained. The scores are displayed as follows:11, 16, 19, 15, 7, 8, 10Test the hypothesis that the mean score is 15 at 1% significance level (b) A chemical manufacturer is concerned about the degree of contamination in the raw materialshipments purchased from a supplier. Taking a random sample of 20 shipments of raw materials,the standard deviation of contamination is 3.59. Construct the 95% confidence interval forpopulation variance
6 Given the following data: the first quartile Q1 =(17) and Inter-quartile Range (IQR = 117); Then the third quartile Q3 equals: (Write only the number) Answer:
You may need to use the appropriate technology to answer this question. Information regarding the ACT scores of samples of students in three different majors is given below. esc Sample Size 68°F Clear Average Sample Variance ? (a) Compute the overall sample mean . 29.5 X Between Treatments Management Within Treatments Total f2 12 26 f3 17 # Source of Variation Sum of Squares * (b) Set up the ANOVA table for this problem including the test statistic. (Round your mean squares to four decimal places and your F statistic to two decimal places.) Major Finance 000 F 9 23 $ 6 (c) Using a = 0.01, determine the critical value of F. (Round your answer to two decimal places.) f5 Accounting (d) Using the critical value approach, test to determine whether there is a significant difference in the means of the three populations. O We should not reject H. and therefore can conclude that there is a significant difference among the means of the three populations. We should not reject Ho and therefore…
Question 20. part b. Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 14 randomly selected patients who went to the emergency room at rural hospitals waited an average of 5.8 hours to be admitted into the hospital. The standard deviation for these 14 patients was 1.7 hours. What can be concluded at the the αα = 0.05 level of significance level of significance? C.)The test statistic ?, z or t = ____ (please show your answer to 3 decimal places.) D.)The p-value = ______ (Please show your answer to 4 decimal places.) E.) The p-value is ?, ≤ , > α

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