Answer problem 3
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Answer problem 3
![2. The resultant of the concurrent forces shown in figure below is 300 lb pointing up along
the y-axis. Compute the values of F and e required to give this resultant. ( Answer: F=
512 Ib up to the right at e, = 55.2°)
Forces
X-comp
y-comp
500 b
500 Ib
240 lb
240 lb
Rx= 0
Ry = 300 lb
R= 300 b,
e = 90 (upward)
Page | 1
3. Repeat problem No. 2 if the resultant is 400 lb down to the right at 60° with the x-axis.
Forces
x-comp
усomp
500 lb
500 Ib
240 lb
Rx =
Ry =
240 lb
R= 400 lb,
e = 60°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a743ba9-d975-4b01-a004-067d2ac505b6%2F35b42c4d-b941-43c8-a6bc-c0a9d1fc5e06%2Faax3dfp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. The resultant of the concurrent forces shown in figure below is 300 lb pointing up along
the y-axis. Compute the values of F and e required to give this resultant. ( Answer: F=
512 Ib up to the right at e, = 55.2°)
Forces
X-comp
y-comp
500 b
500 Ib
240 lb
240 lb
Rx= 0
Ry = 300 lb
R= 300 b,
e = 90 (upward)
Page | 1
3. Repeat problem No. 2 if the resultant is 400 lb down to the right at 60° with the x-axis.
Forces
x-comp
усomp
500 lb
500 Ib
240 lb
Rx =
Ry =
240 lb
R= 400 lb,
e = 60°
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