Answer Length of the string =L = 4m In f(hz) u(kg/m) F(N) A(m) vO(m/s) 1 53.25 0.00012 19.9 426 59.85 0.00064 37 4 239.4 3 65.63 0.0011 33.85 2.67 175.01 4 90.38 0.00142 46.45 2 180.76 Sample Calculation When f = 53.25 Hz, u= 0.00012 kg/m and F= 19.9 IN Here this is the fundamental mode Length L = /2 A= 2L = 2°4 = 8m vO = f A = 53.25*8 = 426 m/s 19.9 0.00012 = 407.23 m/s % error = (426-407.23)*100/426 = 4.4 % Conclusion In this experiment we found the velocity of wave through a tightened string. We used different methods to obtain the velocity and found the final values almast comparable in both metbods

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Electromagnetic Waves

Electromagnetic waves are waves that consist of magnetic field and electric field components perpendicular to each other. These field components are also perpendicular to the direction of propagation of the wave.