Answer Length of the string =L = 4m In f(hz) u(kg/m) F(N) A(m) vO(m/s) 1 53.25 0.00012 19.9 426 59.85 0.00064 37 4 239.4 3 65.63 0.0011 33.85 2.67 175.01 4 90.38 0.00142 46.45 2 180.76 Sample Calculation When f = 53.25 Hz, u= 0.00012 kg/m and F= 19.9 IN Here this is the fundamental mode Length L = /2 A= 2L = 2°4 = 8m vO = f A = 53.25*8 = 426 m/s 19.9 0.00012 = 407.23 m/s % error = (426-407.23)*100/426 = 4.4 % Conclusion In this experiment we found the velocity of wave through a tightened string. We used different methods to obtain the velocity and found the final values almast comparable in both metbods

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Help writing a conclusion for a standing waves on a string experiment.
Answer Length of the string =L = 4m
F(hz) u(kg/m) F(N)
53.25 0.00012 19.9
In
A(m)
vo(m/s) v
1
8
426
4
59.85 0.00064 37
4
239.4
2
65.63 0.0011
33.85 2.67
175.01 1
4
90.38 0.00142 46.45 2
180.76 1
Sample Calculation
When f = 53.25 Hz, µ= 0.00012 kg/m and F=19.9
N
Here this is the fundamental mode Length L=/2
1 = 2L = 2*4 = 8m vo = f A = 53.25*8 = 426 m/s
19.9
0.00012
= 407.23 m/s
% error = (426-407.23)*100/426 = 4.4 % Conclusion
In this experiment we found the velocity of wave
through a tightened string . We used different methods
to obtain the velocity and found the final values almast
comparable in both methods
3)
Transcribed Image Text:Answer Length of the string =L = 4m F(hz) u(kg/m) F(N) 53.25 0.00012 19.9 In A(m) vo(m/s) v 1 8 426 4 59.85 0.00064 37 4 239.4 2 65.63 0.0011 33.85 2.67 175.01 1 4 90.38 0.00142 46.45 2 180.76 1 Sample Calculation When f = 53.25 Hz, µ= 0.00012 kg/m and F=19.9 N Here this is the fundamental mode Length L=/2 1 = 2L = 2*4 = 8m vo = f A = 53.25*8 = 426 m/s 19.9 0.00012 = 407.23 m/s % error = (426-407.23)*100/426 = 4.4 % Conclusion In this experiment we found the velocity of wave through a tightened string . We used different methods to obtain the velocity and found the final values almast comparable in both methods 3)
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