Answer each question below and justify your answer. (a) For which values of n does Cn have an Euler circuit? (b) For which values of n does Cn have an Euler trail? (c) For which values of n does Kn have an Euler circuit? (d) For which values of n does K, have an Euler trail?
Answer each question below and justify your answer. (a) For which values of n does Cn have an Euler circuit? (b) For which values of n does Cn have an Euler trail? (c) For which values of n does Kn have an Euler circuit? (d) For which values of n does K, have an Euler trail?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![### Analyzing Euler Circuits and Trails in Graph Theory
In this section, we will explore the criteria for Euler circuits and Euler trails within two common types of graphs: cycle graphs (Cₙ) and complete graphs (Kₙ).
#### Questions to Consider:
**(a)** For which values of \( n \) does \( C_n \) have an Euler circuit?
- **Explanation**: An Euler circuit exists in a graph if it is connected and every vertex has an even degree. For cycle graphs \( C_n \), every vertex in the cycle has a degree of 2. Therefore, \( C_n \) will have an Euler circuit for all values of \( n \geq 3 \).
**(b)** For which values of \( n \) does \( C_n \) have an Euler trail?
- **Explanation**: An Euler trail exists if a graph is connected and has exactly two vertices of odd degree. In \( C_n \), since every vertex has an even degree, the graph will have an Euler trail only when the conditions for an Euler circuit are satisfied. Thus, \( C_n \) will have an Euler trail for all values of \( n \geq 3 \); however, this is the same condition as having an Euler circuit.
**(c)** For which values of \( n \) does \( K_n \) have an Euler circuit?
- **Explanation**: The complete graph \( K_n \) has an Euler circuit if it is connected and all vertices have even degree. In \( K_n \), each vertex has degree \( n-1 \). Thus, \( K_n \) will have an Euler circuit when \( n-1 \) is even, which occurs when \( n \) is odd (\( n = 2k + 1 \), where \( k \) is an integer).
**(d)** For which values of \( n \) does \( K_n \) have an Euler trail?
- **Explanation**: For \( K_n \) to have an Euler trail, precisely two vertices must have an odd degree, and the rest must have even degrees. Since each vertex in \( K_n \) has degree \( n-1 \), which is odd for even \( n \), all vertices have odd degrees. Hence, no Euler trail exists for any \( n \).
As you explore these concepts, consider how the degree of vertices plays a crucial role in](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb27044a-aee2-4928-a5b3-d202431b45fc%2F6092d659-ccf0-4cfe-848e-2a204c471872%2Fi242q7d_processed.png&w=3840&q=75)
Transcribed Image Text:### Analyzing Euler Circuits and Trails in Graph Theory
In this section, we will explore the criteria for Euler circuits and Euler trails within two common types of graphs: cycle graphs (Cₙ) and complete graphs (Kₙ).
#### Questions to Consider:
**(a)** For which values of \( n \) does \( C_n \) have an Euler circuit?
- **Explanation**: An Euler circuit exists in a graph if it is connected and every vertex has an even degree. For cycle graphs \( C_n \), every vertex in the cycle has a degree of 2. Therefore, \( C_n \) will have an Euler circuit for all values of \( n \geq 3 \).
**(b)** For which values of \( n \) does \( C_n \) have an Euler trail?
- **Explanation**: An Euler trail exists if a graph is connected and has exactly two vertices of odd degree. In \( C_n \), since every vertex has an even degree, the graph will have an Euler trail only when the conditions for an Euler circuit are satisfied. Thus, \( C_n \) will have an Euler trail for all values of \( n \geq 3 \); however, this is the same condition as having an Euler circuit.
**(c)** For which values of \( n \) does \( K_n \) have an Euler circuit?
- **Explanation**: The complete graph \( K_n \) has an Euler circuit if it is connected and all vertices have even degree. In \( K_n \), each vertex has degree \( n-1 \). Thus, \( K_n \) will have an Euler circuit when \( n-1 \) is even, which occurs when \( n \) is odd (\( n = 2k + 1 \), where \( k \) is an integer).
**(d)** For which values of \( n \) does \( K_n \) have an Euler trail?
- **Explanation**: For \( K_n \) to have an Euler trail, precisely two vertices must have an odd degree, and the rest must have even degrees. Since each vertex in \( K_n \) has degree \( n-1 \), which is odd for even \( n \), all vertices have odd degrees. Hence, no Euler trail exists for any \( n \).
As you explore these concepts, consider how the degree of vertices plays a crucial role in
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