Answer D,E,F only. Thank you.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
Answer D,E,F only. Thank you.
Answer (a).
Arrange the observations in ascending order.
The 55th percentile can be calculated as,
Pk=kn+1th100P55=5545+1100=25.3=25th+0.326th-25th=1049+0.3(1063-1049)=1053.2
The 9th decile can be calculated as,
Dk=kn+1th10D9=945+110=41.4=41th+0.442th-41th=1250+0.4(1250-1217)=1230.2
The 3rd
Qk=kn+1th4Q3=345+14=34.5=34th+35th2=1157+11572=1157
Answer (b).
The two observations 521 and 785 are deleted because these observations does not lie in given class interval.
The class width is calculated as,
class width=maximum-minimumnumber of intervals=1340-8017=77
According to class width the class intervals and frequency table is given as,
| class interval | frequency |
| 801-878 | 5 |
| 878-955 | 11 |
| 955-1032 | 5 |
| 1032-1109 | 7 |
| 1109-1186 | 7 |
| 1186-1263 | 5 |
| 1263-1340 | 3 |
Transcribed Image Text:2. Consider the following data representing the life in hours of incandescent bulbs.
1,067
919
1,196
785
1,126
855
1,092
1,162
1,170
929
1,157
1,195
1,195
1,340
1,122
1,022
978
832
1,009
1,157
923
1,333
811
1,217
1,085
521
933
928
1,153
946
930
807
954
1,063
1,002
999
932
1,035
944
1,049
901
1,324
818
1,250
1,203
a. Using ungrouped data, find: P55, D9 and Q3.
b. Use 7 intervals with the lowest starting at 801 hrs., and show the frequency distribution and
cumulative frequency distribution.
c. Create the frequency histogram based on (b).
d. Create the frequency polygon based on (b).
e. Create a stemand leaf plot or double stem and leaf plot.
f. Create box plot.
Transcribed Image Text:12
Histogram
10
8
6
801-878
878-955
I frequency
1032-1109
Class interval
1186-1263
1263-1340
Frequency
4.
2.
955-1032
1109-1186
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