Answer correctly and read carefully deals with the general multiplication rule in probability. question: Find the probability that both dice show a 3. (look at the information provided within the picture.) chose 1 answer choice: A.) P(both 3)= 1\2 B.) P(both 3)= 1\3 C.) P(both 3)= 1\12 D.) P(both 3)= 1\36

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Answer correctly and read carefully deals with the general multiplication rule in probability.

question:

Find the probability that both dice show a 3. (look at the information provided within the picture.)

chose 1 answer choice:

A.) P(both 3)= 1\2

B.) P(both 3)= 1\3

C.) P(both 3)= 1\12

D.) P(both 3)= 1\36

 

What is the probability of flipping a fair coin and getting "heads" twice in
a row? That is, what is the probability of getting heads on the first flip
AND heads on the second flip?
Imagine we had 100 people simulate this and flip a coin twice. On
average, 50 people would get heads on the first flip, and then 25 of them
would get heads again. So 25 out of the original 100 people – or 1/4 of
them – would get heads twice in a row.
-
The number of people we start with doesn't really matter. Theoretically,
1/2 of the original group will get heads, and 1/2 of that group will get
heads again. To find a fraction of a fraction, we multiply.
We can represent this concept with a tree diagram like the one shown
below.
1
1
1
1/2
%3D
2 2
4
H
1/2
1
1
1
1/2
T
2 2
4
1
1
1
1/2
H.
2 2
4
1/2
1 1
1
1/2
2 2
4
Transcribed Image Text:What is the probability of flipping a fair coin and getting "heads" twice in a row? That is, what is the probability of getting heads on the first flip AND heads on the second flip? Imagine we had 100 people simulate this and flip a coin twice. On average, 50 people would get heads on the first flip, and then 25 of them would get heads again. So 25 out of the original 100 people – or 1/4 of them – would get heads twice in a row. - The number of people we start with doesn't really matter. Theoretically, 1/2 of the original group will get heads, and 1/2 of that group will get heads again. To find a fraction of a fraction, we multiply. We can represent this concept with a tree diagram like the one shown below. 1 1 1 1/2 %3D 2 2 4 H 1/2 1 1 1 1/2 T 2 2 4 1 1 1 1/2 H. 2 2 4 1/2 1 1 1 1/2 2 2 4
We multiply the probabilities along the branches to find the overall
probability of one event AND the next even occurring.
For example, the probability of getting two "tails" in a row would be:
1
Р(T and T)
1
1
2 2
4
When two events are independent, we can say that
P(A and B) =
P(A) · P(B)
Be careful! This formula only applies to independent events.
Practice problem 1: Rolling dice
Suppose that we are going to roll two fair 6-sided dice.
Transcribed Image Text:We multiply the probabilities along the branches to find the overall probability of one event AND the next even occurring. For example, the probability of getting two "tails" in a row would be: 1 Р(T and T) 1 1 2 2 4 When two events are independent, we can say that P(A and B) = P(A) · P(B) Be careful! This formula only applies to independent events. Practice problem 1: Rolling dice Suppose that we are going to roll two fair 6-sided dice.
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