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- 2. Find the horizontal force P to start the motion of any part of the system of three blocks resting upon one another as shown. The weight of the blocks are W-300 KN, Ws= 100 KN and Wc =200 KN. Between A and B μ=0.30, between C and B, μ =0.20 and between C and the ground, p=0.10. 1 sni brod nog 02.0-4 B C 05.0-4 Solution: tamos quoy worla bre sosia asquar 005 300 en of jells400 N₁-300 F3 N-300- N₂=300 Assuming B and C will not move. F₁ = 300 (0.30) F₁ = 90 kN ne à bns A zelboß 1 P = 90 kN es ensla berb hebnu 02.0- y elin 05.0= q V in Celpris orllanimetsa MX 008 Assuming C will not move: al 1st F2=400 (0.20) = 80 kN OTE Bm ribirte F₂ vica Assuming the three blocks move: F3 = 0.10 (600) F3 = 60 kN P=60 KN Least force is 60 kN.The motorcycle in the figure has a mass of m1 kg and its center of mass is at G1. The mass of the driver is m2 kg and the center of mass is at G2. Since there is μs between the wheels and the asphalt, determine whether it is possible for the driver to lift the front wheel off the ground. Neglect the mass of the wheels and assume that the front wheel can spin freely. a=0.41 m b= 0.39 m c= 0.75 m d= 0.25 m e=0.58 m m1=120 kg m2= 77 kg μs=0.82The strings AB and AC connect 500-g mass A to the vertical shaft BC. When the shaft rotates with a constant angular velocity of 15 rad/s, the ball has circular motion in the horizontal plane with the strings having angles of a = 55° shown in the figure. Find the tension forces at the strings AB and AC. 500g A uui 00t 00 mm
- The strings AB and AC connect 500-g mass A to the vertical shaft BC. When the shaft rotates with a constant angular velocity of 15 rad/s, the ball has circular motion in the horizontal plane with the strings having angles of a = 55° shown in the figure. Find the tension forces at the strings AB and AC. B 500g 400 mm 400 mm(dynamic)C Aroller of weight 500 N has a radius of 120 mm and is pulled over a step of height 60 mm by a horizontal force P. The magnitude of Pto just start the roller over the step is r= 120 mm B 60 mm
- How much work is done by the force in the spring when the slender rod rotates from the position where e = 28" to the position where 0 = 63°? The spring has a stiffness of k = 157 N/m and is stretched by 0.21 m when e =0°. The spring is connected to a fixed wall, as well as the endpoint of the rod, as shown. The rod can rotate freely about the fixed pin support at O and AO remains horizontal during motion. Take 40= 1.77 m, which is also the length of the rod. Choose the correct answer. Hoeveel arbeid word deur die krag in die veer verrig wanneer die dun staaf vanaf die posisie waar 0 28 na die posisie waar 0 = 63° roteer? Die veer het 'n styfheid van k = 157 N/m en is 0.21 m uitgerek = wanneer 0 0°. Die veer is aan die vaste muur en die endpunt van die staaf verbind, soos aangetoon. Die staaf kan vrylik om die vaste penstut by O roteer en AO bly horisontaal tydens beweging. Neem AO 1.77 m, wat ook die lengte van die staaf is. Kies die korrekte antwoord. 0. Select one: O-271 Joule 244…in the pulley system and the diagram above, assume that the bearings at oh and C are properly aligned and smooth and that T2 =30 N all dimensions in millimeters and the belt tensions are all tangential to the pulleys a. If the shaft runs at a constant speed, determine the tension T1 b draw a free body diagram of the shaft and determine the reactions at bearing sea in terms of the components along the Y and Z axis. Assume neither bearing and oh or see produces an axial thrust10 It is required to balance the system by placing the balancing masses in the planes P and Q.If the balancing masses revolve at radius 250 mm, given that: mA = 150 kg mB = 200 kg mC = 100 kg mD = 250 kg BA = 0° OB = 105° ec = 200° eD = 300° rA = 150mm rB= 200mm rC = 100mm rD = 250 mm rX = rV = 250 mm Then the magnitude of the balance mass mQ equals: R.P. -ve +ve (A) P) 400 500 800 Activate Go to PC s 249 ka
- 4 m 3m m since the space lattice system is in balance OBD determine the forces acting on the bar В 4 m 3 m C = 40 kN· m 2 m 2 m x D P = 10 kNK1=4 K2=1 K3=8 K4=5The beam, uniform in mass, M = 47.6 kg and length L = 10.2 m, hangs by a cable supported at point B, and rotates without friction around point A. On the end far of the beam, an object of mass m = 24.3 kg is hanging. The beam is making an angle of θ = 30.9° at point A with respect to the + x-axis. The cable makes an angle φ = 21.1° with respect to the - x-axis at B. Assume ψ = θ + φ. a. Enter an expression for the lever arm for the weight of the beam, lB, about the point A. b. Find an expression for the lever arm for the weight of the mass, lm. c. Write an expression for the magnitude of the torque about point A created by the tension T. Give your answer in terms of the tension T and the other given parameters and trigonometric functions. d. What is the magnitude, in newtons, of the tension in the cable? e. Enter an expression the horizontal component of the force, Sx, that the wall exerts on the beam at point A in terms of the tension T, given parameters, and variables…