Answer: 81 /82 = Substitute force-temperature deformation relationships into the geometry-of-deformation equation to derive the compatibility equation. Then, find the force in Bar (1), F1, and the force in Bar (2), F2. Be sure to use the correct sign for each force. By convention, a tension force is positive and a compression force is negative. Answers: F1 = kN F2 = kN Find o and o2, the normal stresses in members (1) and (2), respectively. By convention, a tension stress is positive, and a compression stress is negative. Answers: i MPа 02 MPа Determine d1, the deformation of Bar (1). By convention, a deformation is positive for a member that elongates, and it is negative for a member that is shortened. Answer: 81 = i mm Determine the deflection of point D on the rigid bar. In this case, report a downward deflection as a positive value, or an upward deflection as a negative value. Answer: VD = mm

Answer: 81 /82 = Substitute force-temperature deformation relationships into the geometry-of-deformation equation to derive the compatibility equation. Then, find the force in Bar (1), F1, and the force in Bar (2), F2. Be sure to use the correct sign for each force. By convention, a tension force is positive and a compression force is negative. Answers: F1 = kN F2 = kN Find o and o2, the normal stresses in members (1) and (2), respectively. By convention, a tension stress is positive, and a compression stress is negative. Answers: i MPа 02 MPа Determine d1, the deformation of Bar (1). By convention, a deformation is positive for a member that elongates, and it is negative for a member that is shortened. Answer: 81 = i mm Determine the deflection of point D on the rigid bar. In this case, report a downward deflection as a positive value, or an upward deflection as a negative value. Answer: VD = mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Planar Stresses

Question

On a piece of paper, sketch a deformation diagram. Based on this diagram, write a geometry-of-deformation equation in terms of
deformations &1 and 82, which are the deformations of Bars (1) and (2), respectively. From the geometry-of-deformation
equation, enter the ratio, &1 / 82.
Answer: δ /δ-
Substitute force-temperature deformation relationships into the geometry-of-deformation equation to derive the compatibility
equation. Then, find the force in Bar (1), F1, and the force in Bar (2), F2. Be sure to use the correct sign for each force. By
convention, a tension force is positive and a compression force is negative.
Answers:
F1 =
kN
F2 =
kN
Find o, and o2, the normal stresses in members (1) and (2), respectively. By convention, a tension stress is positive, and a
compression stress is negative.
Answers:
MPa
02
MPa
Determine d1, the deformation of Bar (1). By convention, a deformation is positive for a member that elongates, and it is negative
for a member that is shortened.
Answer: 81 = i
mm
Determine the deflection of point Don the rigid bar. In this case, report a downward deflection as a positive value, or an upward
deflection as a negative value.
SE
Answer: VD = i
mm

The pin-connected structure shown consists of a rigid bar ABCD and two axial members. Bar (1) is steel [E = 200 GPa; a = 11.7x
10-6/°C], with a cross-sectional area of A1 = 370 mm2. Bar (2) is an aluminum alloy [E = 70 GPa; a = 22.5 x 10-6/°C], with a cross-
sectional area of A2 = 380 mm?. The bars are unstressed when the structure is assembled. Assume a=360O mm, b=620 mm, c=730
mm, P=20 kN, and L=890 mm. After a concentrated load of P = 20 kN is applied and the temperature is increased by 35°C,
determine
(a) the normal stresses in bars (1) and (2).
(b) the deflection of point D on the rigid bar.
A
(1)
B
(2)

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