[Ans. F, = 19.62 kN, F,= unity. 22. Find the magnitude and direction of the resultant water pressure acting on a curved face of a dam which is shaped WATER SURFACE according to the relation y = as shown in Fig. 3.61. The 12 m height of water retained by the dam is 12 m. Take the width of dam as unity. 23. Each gate of a lock is 5 m high and is sunnorted bu (Ans. 970.74 kN, 0=43° 191
[Ans. F, = 19.62 kN, F,= unity. 22. Find the magnitude and direction of the resultant water pressure acting on a curved face of a dam which is shaped WATER SURFACE according to the relation y = as shown in Fig. 3.61. The 12 m height of water retained by the dam is 12 m. Take the width of dam as unity. 23. Each gate of a lock is 5 m high and is sunnorted bu (Ans. 970.74 kN, 0=43° 191
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![depth of water on the upstream and downstream sides of the lock are 6 m and 4 m respectively. Find:
is 10 m. Each gate is supported by two hinges located at I m and 5 m above the bottom of the lock. The
24. The end gates ABC of a lock are 8 m high and when closed make an angle of 120°. The width of lat
gate, and (i) magnitude of the hinge reactions. [Ans. () 79.279 kN, () Ry=27.924 kN, R,= 51.3SAN
sides of the gates are 4 m and 3 m respectively, determine : (i) the magnitude of resultant pressure on cat
gates are closed, they make an angle of 120°. The width of the lock is 4 m. If the depths of water on the rwe
4m as shown in Fig. 3.60. Consider width of the gate unity.
() Resultant water force on cach gate.
21. Find the horizontal and vertical components of the water pressure exerted on a tainter gate of
[Ans. F,= 19.62 kN, F, =710244N]
22. Find the magnitude and direction of the resultant water
pressure acting on a curved face of a dam which is shaped
WATER SURFACE
according to the relation y = as shown in Fig. 3.61. The
12 m
height of water retained by the dam is 12 m. Take the width
of dam as unity.
23. Each gate of a lock is 5 m high and is supported by two
hinges placed on the top and bottom of the gate. When the
(Ans. 970.74 kN, 0 = 43° 191
Fig. 3.61](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F528ec269-c310-4956-8cd6-e5578d6dcc65%2F6cbfb79a-482e-4d71-953b-af6d8a7c186b%2F24cj7qb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:depth of water on the upstream and downstream sides of the lock are 6 m and 4 m respectively. Find:
is 10 m. Each gate is supported by two hinges located at I m and 5 m above the bottom of the lock. The
24. The end gates ABC of a lock are 8 m high and when closed make an angle of 120°. The width of lat
gate, and (i) magnitude of the hinge reactions. [Ans. () 79.279 kN, () Ry=27.924 kN, R,= 51.3SAN
sides of the gates are 4 m and 3 m respectively, determine : (i) the magnitude of resultant pressure on cat
gates are closed, they make an angle of 120°. The width of the lock is 4 m. If the depths of water on the rwe
4m as shown in Fig. 3.60. Consider width of the gate unity.
() Resultant water force on cach gate.
21. Find the horizontal and vertical components of the water pressure exerted on a tainter gate of
[Ans. F,= 19.62 kN, F, =710244N]
22. Find the magnitude and direction of the resultant water
pressure acting on a curved face of a dam which is shaped
WATER SURFACE
according to the relation y = as shown in Fig. 3.61. The
12 m
height of water retained by the dam is 12 m. Take the width
of dam as unity.
23. Each gate of a lock is 5 m high and is supported by two
hinges placed on the top and bottom of the gate. When the
(Ans. 970.74 kN, 0 = 43° 191
Fig. 3.61
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