Ans. (5) Given position vector r(t) = (t₁ t - sint, 1- cast) ⇒ r (t) = ti + (t-sint) 3 + (1 - cost) k j geven by drit) and velocity v(t) is dt acceleration a (t) is given by Now, Now, Vlt) = dř (t) dt. ⇒ ³ (t) = VU Now a(t) = dv (1) dt a 2 (t) = L d (i dt So, we can write and d V (H) dt d (t dt 1² + (1 - cost)j + (0-(-sist)) k 1 + (1-cost)^3 + sist k (t-sint)j + (1-cost)}) (t 0² + (0+ sint) Ĵ + cost k Oi + sist j + Cost k 1 + (1- cost) if + sint k write √ (1) = (1, 1-cost, sint) a(t) = (0, sint, cost)
Ans. (5) Given position vector r(t) = (t₁ t - sint, 1- cast) ⇒ r (t) = ti + (t-sint) 3 + (1 - cost) k j geven by drit) and velocity v(t) is dt acceleration a (t) is given by Now, Now, Vlt) = dř (t) dt. ⇒ ³ (t) = VU Now a(t) = dv (1) dt a 2 (t) = L d (i dt So, we can write and d V (H) dt d (t dt 1² + (1 - cost)j + (0-(-sist)) k 1 + (1-cost)^3 + sist k (t-sint)j + (1-cost)}) (t 0² + (0+ sint) Ĵ + cost k Oi + sist j + Cost k 1 + (1- cost) if + sint k write √ (1) = (1, 1-cost, sint) a(t) = (0, sint, cost)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
Transcribed Image Text:Ans. (5)
Given position vector r(t) = (t, t - sint, 1-cost)
7² (t) = t i + (t-sint) j +
ti + (t-sint) j + (1 - cost) k
velocity v (t) is given by dirt and
dt
Now,
acceleration à (t) is
given by
dü (t);
dt
Now, V(t) = d7 (2) = d (ti + (t-sint)j + (1-
cost)})
dt
dt
→ √ (t) =
→ V (H)
1² + (1 - cost) j
3 1 ² + (1 - cost); + (0-1-sind) A
1 + (1-cost) j
C
+ sint k
Now a (t) = dv (1)
dt
→ [a (1)
=
So, we can
and
d
dt
(i + (1 - cost) i + sint k
0² + (0+ sint) ↑ + cost k ...
Oi+ sist
4 cast k
J
write ✓(1)
√(t) = (1, 1-cost, sint)
(0, sint, cost)
a(t) =
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