Annual Worth Analysis - 3 A*The AW values of three revenue alternatives are $ 30,000 for A. $ 40,000 for B, and $ 55,000 for C. On the basis of these AW values, the correct decision is to:(a) select alternative A(b). select alternative B.(c) select alternative C(d). select the do-nothing alternative.

The time value of money refers to the concept that tells a sum of money is worth greater now than…

Answered: Annual Worth Analysis - 3 A The AW…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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Two incinerators are being considered by a waste management company. Design A has an initial cost of $2,500,000, has annual operating and maintenance costs of $800,000, and requires overhauls every 5 years at a cost of $1,250,000. Design B is more sophisticated, including computer controls; it has an initial cost of $5,750,000, has annual operating and maintenance costs of $600,000, and requires overhauls every 10 years at a cost of $3,000,000. Using a 5%/year interest rate, determine the capitalized cost for each design and recommend which should be chosen.
Which of the following is not among the measures of worth that are used in engineering economic analysis? Select one: a. payback period b. annual worth c. operations analysis d. future worth
Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with low friction properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 16% per year, which alternative has the better present worth and what is that value (select the closest value)? Method First Cost AOC, per Year Salvage Value Life DDM $170,000 $65,000 $4,000 2 years LS $350,000 $40,000 $29,000 4 years DDM with a PW--$473,000 LS with a PW --$445,900 LS with a PW --$222,055 DDM with a PW--$109,300
Give typing answer with explanation and conclusion
The General Hospital is evaluating new office equipment offered by three companies. Cost Annual benefit End of useful life salvage value Useful life (yrs) Select one: 9.5% 8.5% 7.5% Company A $500 $130 $0 10.5% 5 The incremental rate of return between Company B and Company C is close to Company B $600 $115 $250 5 Company C $700 $100 $180 10
Answer the given question with a proper explanation and step-by-step solution.
A city government feels that the energy production capacity must be expanded to meet anticipated demands for energy. There are three alternatives to consider: @A nuclear facility with an investment of $250 million, operating costs of $3 million per year and life of 20 years. @ A coal plant with an investment of $200 million operating costs of $10 million per year and a life of 20 years. 26°C I P Type here to search
Ee 353.
Most likely estimates for a project are as follows. MARR Useful life Initial investment Receipts - Expenses (R-E) 10% per year 9 years $5,000 $1,200/year Click the icon to view the relationship between the PW and the percent change in parameter. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. (b) To which variable is the PW most sensitive to? OA. Receipts - Expenses OB. Usefule life OC. Initial Investment (a) Determine whether the statement "An initial investment of $6,000 keeps the investment economical." is true or false. O False O True
What is FW of Design A, Design B, and Design C. Which alternative should be chosen. Do not round off in the solution.
Polypropylene wall caps, used for covering exterior vents for kitchen cooktops. bathroom fans, dryers, and other building air exhausts. can be made by two different methods. Method X will have a first cost of $75,000. an operating cost of $32,000 per year, and a $9000 salvage value after 4 years. Method Y will have a first cost of $140,000. an operating cost of $24,000 per year, and a $19,000 salvage value after its 4-year life. At an interest rate of 10% per year, which method should be used on the basis of an annual worth analysis? 10% TABLE 15 Discrete Cash Flow: Compound interest Factors 10% Single Payments Uniform Series Payments Arithmetic Gradients Compound Amount Capital Recovery Present Sinking Fund Compound Amount Present Gradient Gradient Worth Worth Present Worth Uniform Series F/P P/F A/F F/A A/P P/A P/G A/G L1000 110000 0.9091 09091 08264 10000 0.47619 0.30211 10000 04762 0.9366 12100 21000 0.57619 0.40211 1.7355 13310 0.7513 3.3100 2.4869 23291 14641 06830 0.21547 4,6410…

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