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angular diameter (in arc seconds) 2.06 X 105 = linear diameter distance

angular diameter (in arc seconds) 2.06 X 105 = linear diameter distance

Applications and Investigations in Earth Science (9th Edition)
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
Problem 1LR
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A planetary nebula photographed 24 years ago and then photographed again today has increased its radius by 0.4 arc second. If Doppler shifts in its spectrum show that the planetary nebula is expanding at a velocity of 22 km/s, how far away (in pc) is the planetary nebula? (Hints: First determine how many parsecs the planetary nebula has increased in radius over 24 years. Then use the small-angle formula: angular diameter (in arc seconds) 2.06 X 105 = linear diameter distance Answer in Parsecs
Transcribed Image Text:A planetary nebula photographed 24 years ago and then photographed again today has increased its radius by 0.4 arc second. If Doppler shifts in its spectrum show that the planetary nebula is expanding at a velocity of 22 km/s, how far away (in pc) is the planetary nebula? (Hints: First determine how many parsecs the planetary nebula has increased in radius over 24 years. Then use the small-angle formula: angular diameter (in arc seconds) 2.06 X 105 = linear diameter distance Answer in Parsecs
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