angle of 35°, and they move the box a distance of 11 m. How much work did they do? e COTTILIIT F cos 0= F₁ d

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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**Physics Problem: Work Done by a Force**

**Problem Statement:**

9. A person pulls a crate across a floor using a rope. They pull on the rope with a force of 95 N at an angle of 35°, and they move the box a distance of 11 m. How much work did they do?

**Diagram Description:**

The diagram illustrates a person pulling a crate with a rope. The force exerted is shown as a vector \(\vec{F}\) at an angle \(\theta = 35^\circ\) above the horizontal line. The horizontal component of the force is depicted as \(F \cos \theta = F_x\).

- The horizontal line represents the direction of displacement \(d\).

**Solution Explanation:**

To calculate the work done, use the formula:

\[ 
\text{Work} = F_x \times d
\]

Where \(F_x = F \cos \theta\). Therefore, the horizontal component of the force \(F_x\) can be calculated as:

\[ 
F_x = 95 \, \text{N} \times \cos(35^\circ) 
\]

Finally, calculate the work done by multiplying the horizontal component of the force by the distance:

\[ 
\text{Work} = F_x \times 11 \, \text{m}
\]

**Educational Note:**

Work is only done by the component of the force in the direction of the displacement. The angle here indicates that only a portion of the applied force contributes to the work done in moving the crate.
Transcribed Image Text:**Physics Problem: Work Done by a Force** **Problem Statement:** 9. A person pulls a crate across a floor using a rope. They pull on the rope with a force of 95 N at an angle of 35°, and they move the box a distance of 11 m. How much work did they do? **Diagram Description:** The diagram illustrates a person pulling a crate with a rope. The force exerted is shown as a vector \(\vec{F}\) at an angle \(\theta = 35^\circ\) above the horizontal line. The horizontal component of the force is depicted as \(F \cos \theta = F_x\). - The horizontal line represents the direction of displacement \(d\). **Solution Explanation:** To calculate the work done, use the formula: \[ \text{Work} = F_x \times d \] Where \(F_x = F \cos \theta\). Therefore, the horizontal component of the force \(F_x\) can be calculated as: \[ F_x = 95 \, \text{N} \times \cos(35^\circ) \] Finally, calculate the work done by multiplying the horizontal component of the force by the distance: \[ \text{Work} = F_x \times 11 \, \text{m} \] **Educational Note:** Work is only done by the component of the force in the direction of the displacement. The angle here indicates that only a portion of the applied force contributes to the work done in moving the crate.
Expert Solution
Step 1: Given

Applied force (F) = 95 N 

Displacement (d) = 11 m 

Angle (θ) = 35°


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