College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Problem: Work Done by a Force**
**Problem Statement:**
9. A person pulls a crate across a floor using a rope. They pull on the rope with a force of 95 N at an angle of 35°, and they move the box a distance of 11 m. How much work did they do?
**Diagram Description:**
The diagram illustrates a person pulling a crate with a rope. The force exerted is shown as a vector \(\vec{F}\) at an angle \(\theta = 35^\circ\) above the horizontal line. The horizontal component of the force is depicted as \(F \cos \theta = F_x\).
- The horizontal line represents the direction of displacement \(d\).
**Solution Explanation:**
To calculate the work done, use the formula:
\[
\text{Work} = F_x \times d
\]
Where \(F_x = F \cos \theta\). Therefore, the horizontal component of the force \(F_x\) can be calculated as:
\[
F_x = 95 \, \text{N} \times \cos(35^\circ)
\]
Finally, calculate the work done by multiplying the horizontal component of the force by the distance:
\[
\text{Work} = F_x \times 11 \, \text{m}
\]
**Educational Note:**
Work is only done by the component of the force in the direction of the displacement. The angle here indicates that only a portion of the applied force contributes to the work done in moving the crate.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe591ff8b-7fbf-41eb-ab1a-65fc8e854653%2Fcab5bed9-2250-4bee-b2f0-8cb672652940%2Fdwr97j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Problem: Work Done by a Force**
**Problem Statement:**
9. A person pulls a crate across a floor using a rope. They pull on the rope with a force of 95 N at an angle of 35°, and they move the box a distance of 11 m. How much work did they do?
**Diagram Description:**
The diagram illustrates a person pulling a crate with a rope. The force exerted is shown as a vector \(\vec{F}\) at an angle \(\theta = 35^\circ\) above the horizontal line. The horizontal component of the force is depicted as \(F \cos \theta = F_x\).
- The horizontal line represents the direction of displacement \(d\).
**Solution Explanation:**
To calculate the work done, use the formula:
\[
\text{Work} = F_x \times d
\]
Where \(F_x = F \cos \theta\). Therefore, the horizontal component of the force \(F_x\) can be calculated as:
\[
F_x = 95 \, \text{N} \times \cos(35^\circ)
\]
Finally, calculate the work done by multiplying the horizontal component of the force by the distance:
\[
\text{Work} = F_x \times 11 \, \text{m}
\]
**Educational Note:**
Work is only done by the component of the force in the direction of the displacement. The angle here indicates that only a portion of the applied force contributes to the work done in moving the crate.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1: Given
Applied force (F) = 95 N
Displacement (d) = 11 m
Angle (θ) = 35°
Step by step
Solved in 3 steps with 1 images
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