Angel and Barbara were both asked to factor the following polynomial completely. Is one of them correct? Both of them? Neither of them? Explain what each of them did that was correct and/or incorrect. Angel 6x²+20x-16 2(3x²+10x-8) 2( 3x-2)(x+4) Barbara 6x²+20x-16 (6x-4)(x+4)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Question
### Factoring Polynomials: A Comparison of Two Approaches

#### Problem Statement
Angel and Barbara were both asked to factor the following polynomial completely:

\[ 6x^2 + 20x - 16 \]

Is one of them correct? Both of them? Neither of them? Explain what each of them did that was correct and/or incorrect.

---

#### Angel's Approach

1. **Initial Polynomial:**

\[ 6x^2 + 20x - 16 \]

2. **First Step:**

\[ 2(3x^2 + 10x - 8) \]

3. **Second Step:**

\[ 2 (3x - 2)(x + 4) \]

---

#### Barbara's Approach

1. **Initial Polynomial:**

\[ 6x^2 + 20x - 16 \]

2. **First and Final Step:**

\[ (6x - 4)(x + 4) \]

---

### Analysis and Explanation

#### Angel's Work
Angel started by factoring out a common factor of 2 from the polynomial:

\[ 6x^2 + 20x - 16 \rightarrow 2(3x^2 + 10x - 8) \]

Then, Angel factored the remaining quadratic expression:

\[ 2(3x^2 + 10x - 8) \rightarrow 2(3x - 2)(x + 4) \]

#### Barbara's Work
Barbara directly factored the polynomial as follows:

\[ 6x^2 + 20x - 16 \rightarrow (6x - 4)(x + 4) \]

### Verification of Factoring
To determine if the factored forms are correct, we can expand the expressions and see if they match the original polynomial.

1. **Angel's Factoring:**

\[ 2(3x - 2)(x + 4) \]

   Expanding the terms inside the parentheses first:

\[ (3x - 2)(x + 4) = 3x^2 + 12x - 2x - 8 = 3x^2 + 10x - 8 \]

   Now, multiplying by 2:

\[ 2(3x^2 + 10x - 8) = 6x^2 + 20x - 16 \]

   Angel's fact
Transcribed Image Text:### Factoring Polynomials: A Comparison of Two Approaches #### Problem Statement Angel and Barbara were both asked to factor the following polynomial completely: \[ 6x^2 + 20x - 16 \] Is one of them correct? Both of them? Neither of them? Explain what each of them did that was correct and/or incorrect. --- #### Angel's Approach 1. **Initial Polynomial:** \[ 6x^2 + 20x - 16 \] 2. **First Step:** \[ 2(3x^2 + 10x - 8) \] 3. **Second Step:** \[ 2 (3x - 2)(x + 4) \] --- #### Barbara's Approach 1. **Initial Polynomial:** \[ 6x^2 + 20x - 16 \] 2. **First and Final Step:** \[ (6x - 4)(x + 4) \] --- ### Analysis and Explanation #### Angel's Work Angel started by factoring out a common factor of 2 from the polynomial: \[ 6x^2 + 20x - 16 \rightarrow 2(3x^2 + 10x - 8) \] Then, Angel factored the remaining quadratic expression: \[ 2(3x^2 + 10x - 8) \rightarrow 2(3x - 2)(x + 4) \] #### Barbara's Work Barbara directly factored the polynomial as follows: \[ 6x^2 + 20x - 16 \rightarrow (6x - 4)(x + 4) \] ### Verification of Factoring To determine if the factored forms are correct, we can expand the expressions and see if they match the original polynomial. 1. **Angel's Factoring:** \[ 2(3x - 2)(x + 4) \] Expanding the terms inside the parentheses first: \[ (3x - 2)(x + 4) = 3x^2 + 12x - 2x - 8 = 3x^2 + 10x - 8 \] Now, multiplying by 2: \[ 2(3x^2 + 10x - 8) = 6x^2 + 20x - 16 \] Angel's fact
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