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and V. 35. 36. 37. = (1,1,1), V = (2,0,1) = (1, -2, 1), V=(3,2,1) =(5, 0, 2), v= (-3,0,7)

and V. 35. 36. 37. = (1,1,1), V = (2,0,1) = (1, -2, 1), V=(3,2,1) =(5, 0, 2), v= (-3,0,7)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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10.4) question 35
= R³ in- 34. =(-1,2,1), V= (2,2,1), W=(3,1,3) In Exercises 35-38, find a unit vector orthogonal to both u and V. 35. = (1, 1, 1), ✔= (2,0,1) 36. = (1, -2,1), V= (3,2,1) 37. ū=(5,0, 2), ✔= (-3,0,7) 38. u = (1, -2, 1), = (-2,4,-2) 39. A bicycle rider applies 150lb of force, straight down, onto a pedal that extends 7in horizontally from the crankshaft. Find the magnitude of the torque applied to the crankshaft. I n, onto ng a 30° e torque to a 10in e that can to a 10in wrench in a confined space, where the direction of ap- plied force makes a 10° angle with the wrench. How much torque is subsequently applied to the wrench? 43. Show, using the definition of the Cross Product, that ü. (ū x V) = 0; that is, that u is orthogonal to the cross product of ū and V. 44. Show, using the definition of the Cross Product, that uxū= 0
Transcribed Image Text:= R³ in- 34. =(-1,2,1), V= (2,2,1), W=(3,1,3) In Exercises 35-38, find a unit vector orthogonal to both u and V. 35. = (1, 1, 1), ✔= (2,0,1) 36. = (1, -2,1), V= (3,2,1) 37. ū=(5,0, 2), ✔= (-3,0,7) 38. u = (1, -2, 1), = (-2,4,-2) 39. A bicycle rider applies 150lb of force, straight down, onto a pedal that extends 7in horizontally from the crankshaft. Find the magnitude of the torque applied to the crankshaft. I n, onto ng a 30° e torque to a 10in e that can to a 10in wrench in a confined space, where the direction of ap- plied force makes a 10° angle with the wrench. How much torque is subsequently applied to the wrench? 43. Show, using the definition of the Cross Product, that ü. (ū x V) = 0; that is, that u is orthogonal to the cross product of ū and V. 44. Show, using the definition of the Cross Product, that uxū= 0
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