, and they operate independently. The probability that the system will fail is 0.19 the reliability of each of the components?

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**Reliability of Series Components Problem**

1. A system has two components placed in series. Thus, the system will fail as soon as one of the components fails. The two components have the same reliability (i.e., probability of working), and they operate independently. The probability that the system will fail is 0.19. What is the reliability of each of the components?

**Explanation:**

In a series system, the overall system fails if any component within the system fails. Given that the components operate independently with the same reliability, the problem asks us to determine the reliability of each component based on the given probability of overall system failure, which is 0.19.

We can use the concept of complementary probabilities to solve this. The probability that the system works (i.e., does not fail) is complementary to the probability of system failure:

\[ P(\text{System Works}) = 1 - P(\text{System Fails}) = 1 - 0.19 = 0.81. \]

Since the components have the same reliability \( R \) and operate independently, 

\[ R^2 = 0.81. \]

Therefore, 

\[ R = \sqrt{0.81}. \]

Solve for \( R \) to find the reliability of each component.
Transcribed Image Text:**Reliability of Series Components Problem** 1. A system has two components placed in series. Thus, the system will fail as soon as one of the components fails. The two components have the same reliability (i.e., probability of working), and they operate independently. The probability that the system will fail is 0.19. What is the reliability of each of the components? **Explanation:** In a series system, the overall system fails if any component within the system fails. Given that the components operate independently with the same reliability, the problem asks us to determine the reliability of each component based on the given probability of overall system failure, which is 0.19. We can use the concept of complementary probabilities to solve this. The probability that the system works (i.e., does not fail) is complementary to the probability of system failure: \[ P(\text{System Works}) = 1 - P(\text{System Fails}) = 1 - 0.19 = 0.81. \] Since the components have the same reliability \( R \) and operate independently, \[ R^2 = 0.81. \] Therefore, \[ R = \sqrt{0.81}. \] Solve for \( R \) to find the reliability of each component.
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