and Let True or false: y" +p(x)y' +q(x)y=0 y" + p(x)y +q(x)y = g(x) ‡0 1. If y₁ and 2 solve (2), then y = y₁ - y2 solves (1); 2. If y, is a solution of (2), 2y₁ is also a solution of (2); (1) (2) 3. If y₁ and 3₂ are linearly dependent solutions of (1), then y = C₁3₁+C₂Y2 solves (1); 4. Since y₁(x) = 0 is a solution of (1), using reduction of order we can always find the general solution of (1);

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