If I need 240 Fps How to calculate? & (in/in)fps (ksi)0.012300.022550.032600.042640.052680.058270

Given information:To find: when .Concept used:The concept of interpolation will be used to estimate…

Answered: & (in/in) fps (ksi) 0.01 230 0.02 255…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Related questions

Question

If I need 240 Fps How to calculate?

& (in/in)
fps (ksi)
0.01
230
0.02
255
0.03
260
0.04
264
0.05
268
0.058
270

Expert Solution

Step 1: Introduction

Given information:

$epsilon subscript p left parenthesis i n divided by i n right parenthesis$	$0.01$	$0.02$	$0.03$	$0.04$	$0.05$	$0.058$
$f subscript p s end subscript left parenthesis k s i right parenthesis$	$230$	$255$	$260$	$264$	$268$	$270$

To find:

$epsilon subscript p$ when $f subscript p s end subscript equals 240 space k s i$ .

Concept used:

The concept of interpolation will be used to estimate the value of $epsilon subscript p$ for the given $f subscript p s end subscript$ by approximating it using the provided data points.

Formula used:

The Lagrange interpolation polynomial is given by:
$P left parenthesis x right parenthesis equals capital sigma open square brackets f left parenthesis x subscript i right parenthesis cross times L subscript i left parenthesis x right parenthesis close square brackets$
Where:
$P left parenthesis x right parenthesis$ is the interpolated polynomial.
$x subscript i$ are the known data points for $f subscript p s end subscript$ .
$L subscript i left parenthesis x right parenthesis$ are the Lagrange basis polynomials.