Analyze the given function below that takes a list of numbers with size (n) and returns the number of even and odd numbers in the list. Answer the questions below: def function(List):     oddCount = 0     evenCount = 0     for i in range(len(List)):         if List[i]%2 == 0:              evenCount += 1        else:             oddCount += 1    print ('Number of Odds = ', oddCount)    print ('Number of Evens = ', evenCount)    1.  Count the number of steps required by the function in terms of n?     2.  What is the time complexity of the algorithm.    3.  Find number of operations if (n = 100)

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